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sergij07 [2.7K]
3 years ago
9

A salad costs $2. a steak dinner cost 6 times as much. how much does the steak dinner cost?

Mathematics
1 answer:
sesenic [268]3 years ago
7 0
D 12
multiply six times two answer is 12
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vladimir2022 [97]
Substitute the value of the variable into the expression and simplify 37
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2 years ago
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Complete the square to transform the quadratic equation into the form (x – p)2 = q.
ryzh [129]

The transformed equation is:

(x-3)^2 = 23

Step-by-step explanation:

We have to convert the equation in the form

(x-p)^2 = q

Given equation is:

x^2-6x-8 = 6

Adding 8 on both sides

x^2-6x-8+8 = 6+8\\x^2-6x = 14

In the given equation

a = x

b= ?

So,

2.x.b = 6x\\b =\frac{6x}{2x}\\b = 3\\

So 3^2 will be added on both sides

(x)^2-6x+ (3) = 14+ (3)^2\\(x-3)^2 = 14+9\\(x-3)^2 = 23

Hence,

The transformed equation is:

(x-3)^2 = 23

Keywords: Quadratic equation, transformation

Learn more about quadratic equation at:

  • brainly.com/question/5248692
  • brainly.com/question/5223123

#LearnwithBrainly

7 0
3 years ago
What is the distance between the coordinates (5,5) and (7,2)? Round your
sergey [27]

Answer:

3.61 Units

Step-by-step explanation:

4 0
3 years ago
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What is the nth term rule of the quadratic sequence below? 4,15,30,49,72,99,130,...
navik [9.2K]

Answer:

The nth term rule of the quadratic sequence is 2n^{2} +5n-3.

Step-by-step explanation:

We are given the following quadratic sequence below;

4, 15, 30, 49, 72, 99, 130,...

As we know that the formula for the nth term of the quadratic sequence is given by =  an^{2}+bn+c

Firstly, we will find the difference between the term of the given sequence;

1st difference of the given sequence;

(2nd term - 1st term), (3rd term - 2nd term), (4th term - 3rd term), (5th term - 4th term), (6th term - 5th term), (7th term - 6th term)

= (15 - 4), (30 - 15), (49 - 30), (72 - 49), (99 - 72), (130 - 99),....

= (11, 15, 19, 23, 27, 31,.....)

Now, we will find the second difference of the given sequence, i.e;

= (15 - 11), (19 - 15), (23 - 19), (27 - 23), (31 - 27),....

= (4, 4, 4, 4, 4)

Since the differences are same now, so to find the value of a we have to divide the value of second difference by 2, i.e;

The value of a  =  \dfrac{4}{2} = 2

SO, the first term of the nth term rule equation is an^{2} = 2n^{2}.

Now, in the term 2n^{2}, put the value of n = 1, 2, 3, 4 and 5 and then form the sequence, i.e;

If n = 1, then 2n^{2} = 2 \times (1)^{2} = 2

If n = 2, then 2n^{2} = 2 \times (2)^{2} = 8

If n = 3, then 2n^{2} = 2 \times (3)^{2} = 18

If n = 4, then 2n^{2} = 2 \times (4)^{2} = 32

If n = 5, then 2n^{2} = 2 \times (5)^{2} = 50

SO, the sequence formed is (2, 8, 18, 32, 50).

Now, find the difference of this sequence and the original quadratic sequence, i.e;

= (4 - 2), (15 - 8), (30 - 18), (49 - 32), (72 - 50)

= (2, 7, 12, 17, 22)

Now, as we can see that the above sequence resembles the general form of (5n - 3) because:

If we put n = 1, then (5n - 3) = 5 - 3 = 2

If we put n = 2, then (5n - 3) = 10 - 3 = 7 and so on....

From this, we concluded that the value of b and c are 5 and (-3) respectively.

Hence, the nth term rule for the given quadratic sequence is 2n^{2} +5n-3.

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3 years ago
HELP ASAP!! BRAINLIEST
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Answer: red is exponential growth blue is exponential decay and green is neither

Step-by-step explanation:

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