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almond37 [142]
3 years ago
11

What mass of iron(III) oxide will be formed if 9.30 L of oxygen at STP react with excess iron?

Chemistry
1 answer:
iragen [17]3 years ago
4 0

Answer:

12

Explanation:

because that plot and the iron

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The travel of speed of an electromagnetic wave of 2.8cm wavelength and of 1.1×10^10 Hz frequency is.........
AnnZ [28]

Answer:

wer

c=3.00×108 m/s (the speed of light in a vacuum) λ = wavelength in meters ν = frequency in Hertz (Hz) or 1s or s−1 .

Explanation:

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2 years ago
Consider the reaction:
stich3 [128]

Answer:

\large \boxed{\text{-851.4 kJ/mol}}

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

                            2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)

ΔfH°/kJ·mol⁻¹:         0         -824.3         -1675.7         0

\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}

7 0
3 years ago
Describe the results of Ernest Rutherford's gold-foil experiment and explain how his results changed ideas about the distributio
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Physicist Ernest Rutherford<span> established the nuclear theory of the atom with his </span>gold-foil experiment<span>. When he shot a beam of alpha particles at a sheet of </span>gold foil<span>, a few of the particles were deflected. He concluded that a tiny, dense nucleus was causing the deflections.</span>
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3 years ago
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Pls Help me I am stuck on this question.​
kolbaska11 [484]

Answer:

compound is the answer

4 0
3 years ago
Determine the concentration of a solution prepared by diluting 20.0 ml of a 0.200 m rbcl to 250.0 ml. determine the concentratio
pogonyaev
When dealing with making diluted solutions from concentrated solutions, we can use the following formula 
c1v1 = c2v2 
where c1 and v1 are the concentration and volume of the concentrated solution respectively.
c2 and v2 are the concentration and volume of the diluted solution respectively 
substituting these values in the above formula,
20 mL x 0.200 M = C x 250.0 mL 
C = 0.0160 M 
5 0
3 years ago
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