Once the water evaporates, you will start to see the minerals that were present in the water before it changed state. If the water was from the ocean, you will see salt crystals in the evaporated water. If the water was fresh, you may see other minerals typically found in fresh water.
The ph before the addition of any Koh is<u> 10.105.</u>
Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.
After the addition of 50 ml KOH,
moles of KOH = 50 * 0.13 =<u> 6.5 mmol </u>
<u>moles </u><u>of HClO = 50 * 0.13 = 6.5 mmol </u>
occurred hydrolysis solution,
pH = 0.5(14 + pKa + log [base conjugate])
pH = 0.5(14 + (- log (4 * 10^-8)) + log (6.5/(50 + 50)))
pH = <u>10.105</u>
The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.
The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.
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V ( NaOH ) = mL ?
M ( NaOH ) = 0.100 M
V ( HCl ) = 9.00 mL / 1000 => 0.009 L
M ( HCl ) = 0.0500 M
number of moles HCl:
n = M x V
n = 0.009 x 0.0500 => 0.00045 moles HCl
mole ratio:
<span>HCl + NaOH = NaCl + H2O
</span>
1 mole HCl ---------------- 1 mole NaOH
0.00045 moles HCl ----- ??
0.00045 x 1 / 1 => 0.00045 moles of NaOH
M = n / V
0.100 = 0.00045 / V
V = 0.00045 / 0.100
V = 0.0045 L
1 L ------------ 1000 mL
0.0045 L ----- ??
0.0045 x 1000 / 1 => 4.5 mL of NaOH
