By counting the number of crests that pass by a given point in a set amount of time, what you would be calculating?

Chemistry

1 answer:

dimulka [17.4K]2 years ago

6 0

Answer:

Frequency

Explanation:

When we talk about crests, we are referring to the high points of a wave.

We measure wave frequency by counting out the the number of crests (or high points) of a given wave that pass by a given point in a set amount of time. Thus, the higher the number of crests, the greater the frequency of the wave and vice versa.

We define the frequency of a wave as the number of waves that passes by a fixed point within a given period of time.

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Two elements are more likely to be ionically bonded when ....

larisa86 [58]

Answer:

The correct option is: b. the elements in the material are well apart (in different sides) in the periodic table

Explanation:

Ionic bond is a type of chemical bonding that is formed by the transfer of electrons from one atom to another. It is formed between atoms having large electronegativity difference.

The more electronegative atom accepts electrons and becomes a negatively charged anion. Whereas, the less electronegative atom loses electrons and becomes a positively charged cation.

Simply, an ionic bond is formed when the electrons are transferred from a metal to a non-metal, which are present on different sides of the periodic table.

8 0

2 years ago

the first three ionization energies of an element x are 590, 1145, and 4912 kj mol-1. what is the most likely formula of the com

joja [24]

Answer: The chemical formula is $XSO_3$

Explanation:

Ionization energy is defined as the amount of energy that is required to remove an electron from a chemical species.

The ionization energy equation for the given values follow:

$X(g)\rightarrow X^+(g)+e^-;E_I=590kJ/mol$

$X^+(g)\rightarrow X^{2+}(g)+e^-;E_I=1145kJ/mol$

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From the values of ionization energy above, it can be seen that the ionization energy increases as every succeeding electron is removed.

Second ionization energy is a little higher than the first one but there is a huge amount of difference between the third and second ionization energy.

This implies that the ion formed during second ionization energy has a stable configuration and it requires a humongous amount of heat to release the third electron.

Hence, the ion formed will be $X^{2+}$