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scZoUnD [109]
3 years ago
5

Please help me on this question

Mathematics
1 answer:
aev [14]3 years ago
8 0
Ax - 6b = 5c.......ax = 5c + 6b.......x = (5c + 6b) / a
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Which expressions are equivalent to 2 ln a 2 ln b - ln a? Check all that apply. Ln ab2 - ln a ln a 2 ln b ln a2 ln b2 - ln a 2 l
marysya [2.9K]

Equivalent expressions are expressions with same simplified form. Equivalent expressions for the given expression are;

  • Expression 2:  \ln(a) + 2\ln(b) = \ln(a) + \ln(b^2)  = \ln(ab^2)
  • Expression 3:  \ln(a^2) + \ln(b^2) - \ln(a) = \ln(a^2b^2/a) = \ln(ab^2)
  • Expression 5:  \ln(ab^2)

<h3>What are equivalent expressions?</h3>

Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.

To derive equivalent expressions of some expression, we can either make it look more complex or simple. Usually, we simplify it.

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

b = log_a(c)

Some properties of logarithm are:

log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(b^c) = c \times log_a(b)\\\\log_b(b) = 1\\\\ log_a(b) + log_b(c) = log_a(c)

Log with base e = 2.71828.... is written as \ln(x) simply.

The expression given is 2\ln(a) + 2\ln(b) - \ln(a)

We get its simplified form as

2\ln(a) + 2\ln(b) - \ln(a) = \ln(a) + \ln(b^2) = \ln(ab^2)

Simplifying given expressions:

  • Expression 1:  \ln(ab^2) - \ln(a) = \ln(ab^2/a)  = \ln(b^2)

This isn't same as simplified form of original

. Thus , this expression is not equivalent to the given expression.

  • Expression 2:  \ln(a) + 2\ln(b) = \ln(a) + \ln(b^2)  = \ln(ab^2)

This is same as simplified form of original expression. Thus , this expression is equivalent to the given expression.

  • Expression 3:  \ln(a^2) + \ln(b^2) - \ln(a) = \ln(a^2b^2/a) = \ln(ab^2)

This is same as simplified form of original expression. Thus , this expression is equivalent to the given expression.

  • Expression 4:  2\ln(ab) = \ln((ab)^2) = \ln(a^2b^2)

This isn't same as simplified form of original expression. Thus , this expression is not equivalent to the given expression.

  • Expression 5:  \ln(ab^2)

This is same as simplified form of original expression. Thus , this expression is equivalent to the given expression.

Thus, equivalent expressions for the given expression are;

  • Expression 2:  \ln(a) + 2\ln(b) = \ln(a) + \ln(b^2)  = \ln(ab^2)
  • Expression 3:  \ln(a^2) + \ln(b^2) - \ln(a) = \ln(a^2b^2/a) = \ln(ab^2)
  • Expression 5:  \ln(ab^2)

Learn more about equivalent expressions here:

brainly.com/question/10628562

4 0
2 years ago
Rena swims everyday she burns 10.6 calories per minute when swimming and about 15 total calories warming up before she swims m w
Maslowich
The answer is 9+10 your answer should be solved
8 0
3 years ago
Twice the difference of a number and 8 is 6<br><br> Write an equation using variable w
Sauron [17]

Answer:

8w-2=6

Step-by-step explanation:

7 0
3 years ago
17. Julie has $80 in her savings account and plans to save Sr each
marshall27 [118]

Answer:

$8(x + 10)

Step-by-step explanation:

The expression $8x + $80  has two terms. They are $8x and $80.

When you factor an expression, you are looking for numbers that every term in the expression can divide by (and give a whole number).

Just by looking at the terms, you see they both have $ you can factor out. They can both also be divided by 8. This is called taking out a common factor.

$8x + $80     Take out the common factor

= ($8x) / $8 + ($80) / $8

= $8(x + 10)      The common factor goes outside the terms' bracket

This expression can't be factored more because there are no common factors. The binomial also doesn't have square numbers for example, which might make a case where you need to factor further with different methods.

7 0
4 years ago
Teacher has 1p she buys 10 boxes worth 10p how much does she have to pay
Levart [38]
100p? if you would like to explain what the variable p is i could help out
6 0
3 years ago
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