A stone is tied to s string and whirled around in a circle at constant speed. Is the string more likely to break when the circle
1 answer:
You might be interested in
Answer:
The magnitude of the emf induced in the coil is 60 mV.
Explanation:
We have,
Side of the square coil, a = 24 cm = 0.24 m
Number of turns in the coil, N = 2
It is placed in a uniform magnetic field that makes an angle of 60 degrees with the plane of the coil. If the magnitude of this field increases by 6.0 mT every 10 ms, we need to find the magnitude of the emf induced in the coil.
We know that the induced emf is given by the rate of change of magnetic flux throughout the coil. So,
is the angle between magnetic field and the normal to area vector.
But in this case, a uniform magnetic field that makes an angle of 60 degrees with the plane of the coil. So, the angle between magnetic field and the normal to area vector is 90-60=30 degrees.
Now, induced emf becomes :
or
So, the magnitude of the emf induced in the coil is 60 mV. Hence, this is the required solution.
Answer:
A) The circular one
Explanation:
When there is a loop of wire in a magnetic field, and the magnetic flux through the coil changes, an electromotive force is induced in the coil, according to Faraday-Newmann-Lenz law:
where
N is the number of turns in the coil
is the change in magnetic flux through the coil
is the time interval
The variation of flux through a coil can be written as
where
A is the area of the coil
is the change in magnetic field
Here we have three loops of wire: one circular, one rectangular, one square.
The length of the wire used for the 3 loops is the same, therefore their perimeter is also the same.
The change in magnetic flux is directly proportional to the area enclosed by the loop: therefore, the loop that will experience the greatest induced emf is the one having the greatest area.
Since the circle is the 2D figure that maximizes the area for a given perimeter, this means that the circular loop has the greatest area, and so also the greatest induced emf.