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Dahasolnce [82]
3 years ago
15

Define the fundamental difference between kinematics and dynamics. .

Physics
1 answer:
Tcecarenko [31]3 years ago
5 0

In kynematics you describe the motion of particles using vectors and their change in time. You define a position vector r for a particle, and then define velocity v and acceleration a as

v=\frac{dr}{dt} \\

a=\frac{dv}{dt}

In dynamics Newton's laws predict the acceleration for a given force. Knowing the acceleration, and the kynematical relations defines above, you can solve for the position as a function of time: r(t)

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A rock is thrown straight upward off the edge of a balcony that is 5 m above the ground. The rock rises 10 m, then falls all the
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Displacement = distance and direction from the start-point
to the end-point, regardless of the route followed on the way.

From the throw to the 'plop', the displacement is 5 meters down.
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3 years ago
If an object suspended by a scale shows a weight of 3 N in air, and 2 N when submerged in water, the buoyant force on the submer
Alex Ar [27]

Answer:

1 N

Explanation:

Buoyant Force: This is also called upthrust, It can be defined as the force which act upward exerted by a fluid when an object is placed in it.

The S.I unit is Newton.

From the question,

Buoyant force = Weight of the object in air- weight of the object when submerged in water.

U = W-W'.......................... Equation 1

Where U = upthrust, W = weight in air, W' = weight when submerged in water.

Given: W = 3 N, W' = 2 N

Substitute into equation 1

U = 3-2

W = 1 N

7 0
3 years ago
A 1022kg Caprice car stopped at an intersection is rear-ended by a 1620kg ranger truck moving with a speed of 14.5m/s. If the ca
Alika [10]

Answer:

Explanation:

mass of car, m = 1022 kg

mass of truck, M = 1620 kg

initial velocity of truck, U = 14.5 m/s

initial velocity of car, u = 0 m/s

Let the final velocity of car is v and the final velocity of truck is V.

Collision is elastic, so the coefficient of restitution, e = 1

Use conservation of momentum

initial momentum of car + initial momentum of truck = final momentum of car + final momentum of truck

m x u + M x U = m x v + M x V

0 + 1620 x 14.5 = 1022 v + 1620 V

23490 = 1022 v + 1620 V ..... (1)

Use the formula of coefficient of restitution

e = \frac{V_{1}-V_{2}}{u_{2}-u_{1}}

1 (14.5 - 0) = v - V

14.5 = v - V

V = v - 14.5 .... (2)

Put in equation (1)

23490 = 1022 v + 1620 (v - 14.5)

23490 = 1022 v + 1620 v - 23490

46980 = 2642 v

v = 17.8 m/s

Put in equation (2)

V = 17.8 - 14.5

V = 3.3 m/s

Thus, the speed of car is 17.8 m/s and the velocity of truck is 3.3 m/s after collision.

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3 years ago
Can I improve the design of my simple machine? How?
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Answer:

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Explanation:

yan na po answer ko hehehe

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