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4 years ago

What are some interesting facts about electrons?

1 answer:

8 0

-- all electrons are identical
-- electrons have a negative electrical charge
-- the size of the charge is equal to the positive charge on a proton
-- but it takes about 1,840 electrons to make the mass of one proton

You might be interested in

Describe a scientific method

laila [671]

The process of <u>scientific method</u> involves making hypotheses , driving predictions from them as logical consequences , and then carrying out experiments or empirical observations based on those predictions. A hypotheses is a conjecture , based on knowledge obtained while seeking answers to the questions.

7 0

3 years ago

1) A football player kicks a ball at an angle of 30 and gives it a velocity of 15m/s.

mote1985 [20]

Answer:

A) 1.53s

B) 19.8m

C) 2.869m

Explanation:

A) The time of flight for a projectile can be calculated using the formula:

t = 2μsinθ/g

Where; u = velocity

θ = angle

g = acceleration due to gravity (9.8m/s^2)

t = 2 × 15 × sin 30°/9.8

t = 30sin30°/9.8

t = 30 × 0.5/9.8

t = 15/9.8

t = 1.53s

B) The horizontal range (distance) for a projectile can be calculated using the formula:

Range = u²sin2θ/ g

Range = 15² sin 2 × 30 / 9.8

Range = 225 sin 60/9.8

Range = 225 × 0.8660/9.8

Range = 194.855/9.8

Range = 19.8m

C) The maximum height for a projectile can be calculated using the formula:

h = u²sin²θ/2g

h = 15² (sin 30)² / 2 × 9.8

h = 225 × 0.25 / 19.6

h = 56.25/19.6

h = 2.869m

3 0

4 years ago

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of g

Morgarella [4.7K]

Here is the full question:

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:

$k=\sqrt{\frac{I}{M} }$

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.

Answer:

a) 0.85 m

b) 0.98 m

c) 0.76 m

Explanation:

Given that: the radius of gyration $k=\sqrt{\frac{I}{M} }$

So, moment of rotational inertia (I) of a cylinder about it axis = $\frac{MR^2}{2}$

$k=\sqrt{\frac{\frac{MR^2}{2}}{M} }$

$k=\sqrt{{\frac{MR^2}{2}}* \frac{1}{M} }$

$k=\sqrt{{\frac{R^2}{2}}$

$k={\frac{R}{\sqrt{2}}$

$k={\frac{1.20m}{\sqrt{2}}$

k = 0.8455 m

k ≅ 0.85 m

For the spherical shell of radius

(I) = $\frac{2}{3}MR^2$

$k = \sqrt{\frac{\frac{2}{3}MR^2}{M} }$

$k = \sqrt{\frac{2}{3} R^2}$

$k = \sqrt{\frac{2}{3} }*R$

$k = \sqrt{\frac{2}{3}} *1.20$

k = 0.9797 m

k ≅ 0.98 m

For the solid sphere of radius

(I) = $\frac{2}{5}MR^2$

$k = \sqrt{\frac{\frac{2}{5}MR^2}{M} }$

$k = \sqrt{\frac{2}{5} R^2}$

$k = \sqrt{\frac{2}{5} }*R$

$k = \sqrt{\frac{2}{5}} *1.20$

k = 0.7560

k ≅ 0.76 m

6 0

4 years ago

What mass of silver can be plated onto an object in 33.5 minutes at 8.70 a of current? ag (aq e- ? ag(s what mass of silver can

Schach [20]

To determine the mass plated, we use Faraday's Law of Electrolysis. We calculate as follows:

q = It
q = 8.70 (33.5) (60)
q = 17487 C

mass = 17487 C ( 1 mol e- / 96500 C) ( 1 mol / 2 mol e-) (107.9 g /mol)
mass = 9.78 g

Hope this helps.

4 0

3 years ago

Read 2 more answers

Notice that the speed halfway down is not half the final speed. Another interesting point is that the final answer doesn't depen

ValentinkaMS [17]

Answer:

its speed is insignificant before the diver's speed change, so the result does not change

Explanation:

In this exercise of conservation of the momentum, the system is formed by the diver and the Earth

initial instant (before jumping)

p₀ = 0

final instant (after jumping)

$p_{f}$ = m v + M v²

how momentum is conserved

p₀ = p_{f}

0 = m v + M v²

v² = m / M v

since the mass of the Earth is M = 10²⁴ kg

its speed is insignificant before the diver's speed change, so the result does not change

7 0

3 years ago