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musickatia [10]
2 years ago
14

You may have to_______

Engineering
1 answer:
cluponka [151]2 years ago
5 0
B. Shim you would put shims under the cabinet level
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A bicycle has tires that are 26 inches in diameter. The while in motion, the tires rotate through 125 complete revolutions. How
Stolb23 [73]

Answer:

850.8480103 feet

Explanation:

First you take the diameter and find the circumference, which is (2)(pi)(r) plug in your r which is 26/2= 13 so 2(13)(pi) and multiply taht by 125 after that take your answer and divide by 12which is 850.8480103

3 0
2 years ago
Which of the following best reflects a shield system?
Dafna11 [192]
C, because a narrow structure evacuation below surface ground isn’t the best and a structure holding forces and isn’t to do with the question at all and d doesn’t matter if there include away or not
8 0
3 years ago
In the LC-3 data path, the output of the address adder goes to both the MARMUX and the PCMUX, potentially causing two very diffe
dangina [55]

Answer:

no need for that

Explanation:

they are not the same at all

3 0
2 years ago
When your complex reaction time is compromised by alcohol, an impaired person's ability to respond to emergency or unanticipated
babunello [35]

Answer:

decreased

Explanation:

when impaired you react slower then you would sober.

3 0
3 years ago
An oxygen–nitrogen mixture consists of 35 kg of oxygen and 40 kg of nitrogen. This mixture is cooled to 84 K at 0.1 MPa pressure
Tamiku [17]

Answer:

The mass of oxygen in liquid phase = 14.703 kg

The mass of oxygen in the vapor phase = 20.302 kg

Explanation:

Given that:

The mass of the oxygen m_{O_2} = 35 kg

The mass of the nitrogen m_{N_2} = 40 kg

The cooling temperature of the mixture T = 84 K

The cooling pressure of the mixture P = 0.1 MPa

From the equilibrium diagram for te-phase mixture od oxygen-nitrogen as 0.1 MPa graph. The properties of liquid and vapor percentages are obtained.

i.e.

Liquid percentage of O_2 = 70% = 0.70

Vapor percentage of O_2 = 34% = 0.34

The molar mass (mm) of oxygen and nitrogen are 32 g/mol and 28 g/mol respectively

Thus, the number of moles of each component is:

number of moles of oxygen = 35/32

number of moles of oxygen =  1.0938 kmol

number of moles of nitrogen = 40/28

number of moles of nitrogen = 1.4286  kmol

Hence, the total no. of moles in the mixture is:

N_{total} = 1.0938+1.4286

N_{total} = 2.5224 \ kmol

So, the total no of moles in the whole system is:

N_f + N_g = 2.5224 --- (1)

The total number of moles for oxygen in the system is

0.7 \ N_f + 0.34 \ N_g =  1.0938 --- (2)

From equation (1), let N_f = 2.5224 - N_g, then replace the value of N_f into equation (2)

∴

0.7(2.5224 - N_g) + 0.34 N_g = 1.0938

1.76568 - 0.7 N_g + 0.34 N_g = 1.0938

1.76568 - 0.36 N_g = 1.0938

1.76568 - 1.0938 = 0.36 N_g

0.67188  = 0.36 N_g

N_g = 0.67188/0.36

N_g = 1.866

From equation (1)

N_f + N_g = 2.5224

N_f + 1.866 = 2.5224

N_f = 2.5224 - 1.866

N_f = 0.6564

Thus, the mass of oxygen in the liquid and vapor phases is:

m_{fO_2} = 0.7 \times 0.6564 \times 32

m_{fO_2} = 14.703 \ kg

The mass of oxygen in liquid phase = 14.703 kg

m_{g_O_2} = 0.34 \times 1.866 \times 32

m_{g_O_2} = 20.302 \ kg

The mass of oxygen in the vapor phase = 20.302 kg

8 0
3 years ago
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