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Ne4ueva [31]
3 years ago
15

Explain the particles in Solutions of sodium sulfate alone and lead nitrate alone explain what happens to these particles of the

two solutions are added together steered then allowed to sit for a couple minutes
Chemistry
1 answer:
Inga [223]3 years ago
7 0

Answer:

white precipitates of PbSO4 will appear

Explanation:

Now let us first consider the reaction equation;

Na2SO4(aq) + Pb(NO3)2(aq) ---->2NaNO3(aq) + PbSO4(s)

So, if i mix solutions of sodium sulfate and lead II nitrate, stir it and allow it to stand for a couple of minutes, i will begin to see the appearance of white precipitates of PbSO4.

This follows from the solubility rules. Sulphates are soluble in water except those of group II ions, Pb^2+ and silver I ion.

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Albus Dumbledore provides his students with a sample of 19.3 g of sodium sulfate. How many oxygen atoms are in this sample
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Answer:

<em>3.27·10²³ atoms of O</em>

Explanation:

To figure out the amount of oxygen atoms in this sample, we must first evaluate the sample.

The chemical formula for sodium sulfate is <em>Na₂SO₄, </em>and its molar mass is approximately 142.05\frac{g}{mol}.

We will use stoichiometry to convert from our mass of <em>Na₂SO₄ </em>to moles of <em>Na₂SO₄</em>, and then from moles of <em>Na₂SO₄ </em>to moles of <em>O </em>using the mole ratio; then finally, we will convert from moles of <em>O </em>to atoms of <em>O </em>using Avogadro's constant.

19.3g <em>Na₂SO₄</em> · \frac{1 mol Na^2SO^4}{142.05g Na^2SO^4} · \frac{4 mol O}{1 mol Na^2SO^4} ·\frac{6.022x10^2^3}{1 mol O}

After doing the math for this dimensional analysis, you should get a quantity of approximately <em>3.27·10²³ atoms of O</em>.

3 0
4 years ago
Convert 5.0x10^24 molecules to liters.
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To convert the given value we need conversion factors to relate molecules to liters. At STP, we know that 1 mol is equal to 22.4 L  and by using Avogadro's number we can relate molecules to 1 mol. Calculation is as follows:

5.0x10^24 molecules ( 1 mol / <span>6.022 x 10^23 molecules<span> ) ( 22.4 L / 1 mol) = 186.0 L </span></span>
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