I cant entirely tell for now but an article on rodioactivity should solve the problem
Answer:
[H2] = 0.012 M
[N2] = 0.019 M
[H2O] = 0.057 M
Explanation:
The strategy here is to account for the species at equilibrium given that the concentration of [NO]=0.062M at equilibrium is known and the quantities initially present and its stoichiometry.
2NO(g) + 2H2(g) ⇒ N2(g) + 2H2O(g)
i mol 0.10 0.050 0.10
c mol -0.038 -0.038 +0019 +0.038
e mol 0.062 0.012 00.019 0.057
Since the volume of the vessel is 1.0 L, the concentrations in molarity are:
[NO] = 0.062 M
[H2] = 0.012 M
[N2] = 0.019 M
[H2O] = 0.057 M
Temperature is a measurement of average kinetic energy of the particles in a sample which means that the sample with the highest temperature has the highest average kinetic energy of the particles.
That being said the answer would be 4) 10 mL of H2O (l) at 35 degrees Celsius since that sample has the largest temperature.
I hope this helps. Let me know if anything is unclear.
