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2 years ago

Explain constant and changing velocity.

Physics

2 answers:

Igoryamba2 years ago

7 0

Answer:

To summarize, an object moving in a uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of the object is constant, its velocity is changing. Velocity, being a vector, has a constant magnitude but a changing direction.

alina1380 [7]2 years ago

3 0

Answer:

In order for the velocity to be constant, the magnitude of the velocity (or speed) and the direction of the velocity must not change. Therefore, an object that travels with constant velocity covers the same distance during each time interval and moves in the same direction during the same time interval.

Explanation:

<em>Credit to the person who wrote the comment on your problem, i wrote it here so it is easier seen</em>

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A spacecraft in the shape of a long cylinder has a length of 100 m, and its mass with occupants is 1 480 kg. It has strayed too

maks197457 [2]

Answer:

2352645198509.9604 m/s²

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = $90\times 1.989\times 10^{30}\ kg$

$R_{f}$ = 10000+100 m

$R_{sb}$ = Distance between the nose and the center of the black hole = 10000 m

The difference in the gravitational field in this system is given by

$\Delta F=\dfrac{GMm}{R_{f}^2}-\dfrac{GMm}{R_{sb}^2}\\\Rightarrow \Delta g=GM\left(\frac{1}{R_f^2}-\frac{1}{R_{sb}^2}\right)\\\Rightarrow g=6.67\times 10^{-11}\times 90\times 1.989\times 10^{30}\left(\frac{1}{(10000+100)^2}-\frac{1}{10000^2}\right)\\\Rightarrow \Delta g=-2352645198509.9604\ m/s^2$

The acceleration is 2352645198509.9604 m/s²

4 0

2 years ago

New 5G networks utilize millimeter-wave radiation. Millimeter-wave radiation refers to electromagnetic waves with frequencies in

seraphim [82]

Answer:

It corresponds to 1mm-10 mm range.

Explanation:

Electromagnetic waves (such as the millimeter-wave radiation) travel at the speed of light, which is 3*10⁸ m/s in free space.
As in any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:

$v = \lambda * f (1)$

Replacing v= c=3*10⁸ m/s, and the extreme values of f (which are givens), in (1) and solving for λ, we can get the free-space wavelengths that correspond to the 30-300 GHz range, as follows:

$\lambda_{low} = \frac{c}{f_{high}} = \frac{3e8m/s}{300e9Hz} = 1 mm (2)$

$\lambda_{high} = \frac{c}{f_{low}} = \frac{3e8m/s}{30e9Hz} = 10 mm (3)$

4 0

2 years ago

A small artery has a length of 1.10 × 10-3 m and a radius of 2.50 × 10-5 m. If the pressure drop across the artery is 1.15 kPa,

levacccp [35]

Answer:

$7.69533\times 10^{-11}\ m^3/s$

Explanation:

P = Pressure difference = 1.15 kPa

r = Radius = $2.5\times 10^{-5}\ m$

$\eta$ = Viscosity of liquid = $2.084\times 10^{-3}\ Pas$

l = Length of artery = $1.1\times 10^{-3}\ m$

From Poiseuille's equation we have

$Q=\frac{\pi Pr^4}{8\eta l}\\\Rightarrow Q=\frac{\pi 1.15\times 10^3\times (2.5\times 10^{-5})^4}{8\times 2.084\times 10^{-3}\times 1.1\times 10^{-3}}\\\Rightarrow Q=7.69533\times 10^{-11}\ m^3/s$

The flow rate of blood is $7.69533\times 10^{-11}\ m^3/s$

8 0

2 years ago

Discuss 2 ways tolerance and empathy counteract discrimination in school and community<br>

VladimirAG [237]

Answer:

Reducing Discrimination by Changing Social Norms

Reducing Prejudice through Intergroup Contact

Explanation:

3 0

2 years ago

The energy of the electron in a hydrogen atom can be calculated from the Bohr formula: In this equation stands for the Rydberg e

labwork [276]

Answer:

Wavelength, $\lambda=657\ nm$

Explanation:

The energy of the electron in a hydrogen atom can be calculated from the Bohr formula as :

$E=\dfrac{-R}{n^2}$ .............(1)

Where

R is the Rydberg constant

n is the number of orbit

We need to find the wavelength of the line in the absorption line spectrum of hydrogen caused by the transition of the electron from an orbital with to an orbital with n₁ = 2 to an orbital with n₂ = 3.

Equation (1) can be re framed as :

$\dfrac{1}{\lambda}=R(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2})$

$\dfrac{1}{\lambda}=1.096\times 10^7\times (\dfrac{1}{2^2}-\dfrac{1}{3^2})$

$\lambda=6.569\times 10^{-7}\ m$

$\lambda=657\ nm$

So, the the wavelength of the line in the absorption line spectrum is 657 nm. Hence, this is the required solution.

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3 years ago