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Murljashka [212]
2 years ago
5

Explain constant and changing velocity.

Physics
2 answers:
Igoryamba2 years ago
7 0

Answer:

To summarize, an object moving in a uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of the object is constant, its velocity is changing. Velocity, being a vector, has a constant magnitude but a changing direction.

alina1380 [7]2 years ago
3 0

Answer:

In order for the velocity to be constant, the magnitude of the velocity (or speed) and the direction of the velocity must not change. Therefore, an object that travels with constant velocity covers the same distance during each time interval and moves in the same direction during the same time interval.

Explanation:

<em>Credit to the person who wrote the comment on your problem, i wrote it here so it is easier seen</em>

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Jack and Jill are maneuvering a 3300 kg boat near a dock. Initially the boat's position is &lt; 2, 0, 3 &gt; m and its speed is
Paraphin [41]

Answer:

The workdone by Jack is  W_{jack} = -1050J

The workdone by Jill is  W_{Jill} = 0J

The final velocity is  v = 1.36 m/s

Explanation:

From the question we are given that

          The mass of the boat is m_b = 3300kg

          The initial position of the boat is   P_i  = (2 \r  i  + 0 \r j + 3\r k)m

           The Final position of the boat is  P_f = (4\r i + 0 \r j + 2\r k )\ m

           The Force exerted by Jack \r F = (-420\r i + 0 \r j + 210\r k) \ N

             The Force exerted by Jill  \r F_{Jill} =(180 \r i + 0\r j + 360\r k)

Now to obtain the displacement made we are to subtract the final position from the initial position

                                 \r P = P_f - P_i

                                    = (4\r i + 0\r j + 2 \r k) - (2\r i + 0\r j + 3\r k  )

                                     = (2\r i + 0\r j -\r k )m

Now that we have obtained the displacement we can obtain the Workdone

  which is mathematically represented as

                                                   W =\r  F * \r P

 The amount of workdone by jack would be

                                               W_{jack} =\r  F * \r P

                                                 = [(-420\r i +0\r j +210\r k)(2\r  i + 0\r j - \r k)]

                                                 = (-420) (2) + (210)(-1)

                                                = -840 - 210

                                               =-1050J

  The amount of workdone by Jill would be

                                                 W_{Jill} =\r  F * \r P

                                                        = [(180 \r i + 0\r j + 360\r k)(2\r i +0\r j -\r k)]

                                                       = (180 )(2) +(360)(-1)

                                                       =0J

According to work energy theorem the Workdone is equal to the kinetic energy of the boat

              W = K.E = \frac{1}{2} m *[v^2 - (1.1)^2]

             -1050  = 0.5*3300 [*v^2- (1.1)^2]

            -1050 = 1650 [v^2 -1.21]

               0.6363 = v^2 -1.21

                   v^2 = 0.6363+1.21

                    v^2 =1.846

                    v = 1.36\ m/s

                   

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Answer:

5 ) The mass, 6) with lubrication and using surfaces that are not rough

Explanation:

5) If two bodies are held regardless of their densities and can be combined by some chemical or physical process, the only physical property to be modified will be the mass of the resulting body.

8)

Friction depends on the contact between two surfaces and when a body has a relative motion with respect to a contact surface. In order to reduce friction the contact surface must be lubricated, also the friction depends on the coefficient of friction between surfaces and the normal force exerted by the surface parallel to the area of contact with the body. Mathematically it can be expressed with the following equation.

F_{f} = u*N\\where:\\u = friction coefficient\\N = normal force [Newtons]\\F_{f}= friction force [Newtons]

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3 years ago
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Stels [109]
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