Use the projectile motion equations
H = v^2 x sin^2(θ) ÷ 2g
t = 2 x v x sinθ ÷ g
R = v^2 x sin2θ ÷ g
Answer:
So, the radius of fifth Bohr orbital of hydrogen is 1. 3225 nm.
Explanation:
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Answer:
Put the rest of the equation
Explanation:
You asked the question twice I answered it on the last one
