Answer:
Zinc oxide is the antimicrobial in the medicated foot powder.
Explanation:
Zinc oxide (ZnO) is used to treat several skin conditions such as acne, dermatitis, eczema, etc because it has antibacterial and antifungal properties. This property of the ZnO depends on its size i.e., the smaller the size of ZnO, the stronger antimicrobial activity it has. So, the ZnO nanoparticles are more efficient.
The zinc oxide interacts with the sulfur atoms in microbial proteins and denatures them and destroys their function. This action completely inhibits microbial growth. The treatment with zinc oxide causes the reduced production of conidia in fungi, damages their hyphae and inhibits their ability to produce mycotoxins.
The compounds containing zinc such as ZnSO4, Zn(ClO4)2, etc also have antifungal and antimycotoxin properties that can cause changes in the fungi cell structure. Also, the free radicals formed on the surface of the ZnO nanoparticles can cause damage to the lipids in the bacterial cell membranes that can lead to the leakage and breakdown of the bacterial cell membranes.
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Answer:
Explanation:
The molar mass is the mass of a substance in grams per mole.
To find it, add the mass of each element in the compound. These masses can be found on the Periodic Table.
The compound given is:
The compound has 1 Ca (calcium) and 2 Cl (chlorine).
Mass of Calcium
- The molar mass of calcium is 40.08 g/mol
- There is only one atom of Calcium in CaCl₂, so the number above is what we will use.
Mass of Chlorine
- The molar mass of chlorine is 35.45 g/mol
- There are two atoms of chlorine in CaCl₂, therefore we need to multiply the molar mass by 2.
- 35.45 * 2= 70.9 g/mol
Molar Mass of CaCl₂
- Now, to find the molar mass, add the molar mass of 1 calcium and 2 chlorine.
- 40.08 g/mol + 70.9 g/mol =110.98 g/mol
The molar mass of CaCl₂ is <u>110.98 grams per mole. </u>
Answer:
A transition to renewable energy and to replace fossil fuels would take care of economically producing fine greens. Also, a transition to energy conservation and efficient energy use would help in this process.
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Answer:
2.44 K IS THE TEMPERATURE OF THE GAS
Explanation:
PV = nRT
P = 0.5 atm
V = 2 L
n = 5 moles
R = 0.082 L atm mol^-1 K^-1
T = ?
Substituting for T in the equation, we obtain:
T = P V / nR
T = 0.5 * 2 / 5 * 0.082
T = 1 / 0.41
T = 2.44 K
The temperature of the gas is 2.44 K
