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3 years ago

What is the average acceleration of a rocket that travels 400m in 5s if it starts from rest?

Physics

1 answer:

Pavel [41]3 years ago

4 0

Answer:

Explanation:

We want to find the acceleration based on the given data

Given

distance s=400m

time t= 5s

u= 0m/s since it started from rest

We apply the following expression

s=ut+1/2at^2

substituting we have

400=0*5+1/2*a(5)^2

400=25a/2

cross multiply

25a=400*2

25a=800

divide both sides by 25 we have

a=800/25

a=32m/s^2

The acceleration is 32m/s^2

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Answer:

The value of radiation pressure is $2.933 \times 10^{-8}$ Pa

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Given:

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Put all values in above equation,

$P = \frac{8.8}{3 \times 10^{8} }$

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3 years ago

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3 years ago

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2 years ago

The world's fastest production sportscar has a top speed of 415 kmh-1(a)Convert this speed to ms-1.[ 1](b)The distance from Lond

Alex73 [517]

Answer:

(a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

Explanation:

Given that,

Top speed = 415 km/h

1 miles = 1609 m

(a). We need to calculate the speed in m/s

Using conversion of km/h to m/s

$v=415\ km/h$

$v=415\times\dfrac{5}{18}$

$v=115.28\ m/s$

(b). We need to calculate the distance from London to Edinburgh in km

Using conversion for distance

$d=403\ miles$

Distance in meter,

$d=403\times1609$

$d=648427\ m$

$d=648.427\ km$

We need to calculate the time

Using formula of time

$t=\dfrac{d}{v}$

Put the value into the formula

$t=\dfrac{648.427}{415}$

$t=1.56\ h$

$t=1\ hours 34\ min$

$t= 94\ min$

(c). Speed v' =7.66 km/s

v'=7660 m/s

In the time it takes the car to travel from London to Edinburgh,

We need to calculate the distance

Using formula of distance

$d'=v'\times t$

Put the value into the formula

$d'=7660\times94\times60$

$d'=43202400\ m$

$d'=43202.400\ km$

(d). Speed :

Speed is equal to the distance divided by time.

It is scalar quantity.

Velocity :

Velocity is equal to the displacement divided by time.

It is vector quantity.

Hence, (a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

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3 years ago

A 12.0-cm long cylindrical rod has a uniform cross-sectional area A = 5.00 cm2. However, its density increases linearly from 2.6

andriy [413]

Answer:

(a) The constants required describing the rod's density are B=2.6 and C=1.325.

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Explanation:

(a) Since the density variation is linear and the coordinate x begins at the low-density end of the rod, we have a density given by

$2.6\frac{g}{cm^3}+\frac{18.5\frac{g}{cm^3}-2.6\frac{g}{cm^3}}{12 cm}x = 2.6\frac{g}{cm^3}+1.325x\frac{g}{cm^2}$

recalling that the coordinate x is measured in centimeters.

(b) The mass of the rod can be found by having into account the density, which is x-dependent, and the volume differential for the rod:

$m=\int\rho dv=\int\left(B+Cx\right)Adx=5\int_0^{12}\left(2.6+1.325x\right)dx=126.6$ ,

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3 years ago

What is the average acceleration of a rocket that travels 400m in 5s if it starts from rest?​

What is the average acceleration of a rocket that travels 400m in 5s if it starts from rest?