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Mumz [18]
3 years ago
7

What is the average acceleration of a rocket that travels 400m in 5s if it starts from rest?​

Physics
1 answer:
Pavel [41]3 years ago
4 0

Answer:

<h2>32m/s^2</h2>

Explanation:

We want to find the acceleration based on the given data

Given

distance s=400m

time t= 5s

u= 0m/s since it started from rest

We apply the following expression

s=ut+1/2at^2

substituting we have

400=0*5+1/2*a(5)^2

400=25a/2

cross multiply

25a=400*2

25a=800

divide both sides by 25 we have

a=800/25

a=32m/s^2

The acceleration is 32m/s^2

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8 0
3 years ago
An object accelerating at 16 m/s/s doubles its mass and triples its net force acting on it. What will the new acceleration be? (
nataly862011 [7]

Answer:

24 m/s²

Explanation:

The given parameters are;

The initial acceleration of the object, a = 16 m/s²

Let 'm' represent the initial mass of the object

The initial force acting on the object, F = m × a

∴ F = 16 × m = 16·m

When the mass is doubled, we have;

The new mass of the object, m₂ = 2 × m = 2·m

When the net force acting on the object triples, we have;

The new net force acting on the object, F₂ = 3 × F = 3 × 16·m = 48·m

From F = m × a, we have;

a = F/m

∴ The new acceleration of the object, a₂ = F₂/m₂

From which, by plugging in the values, we have;

a₂ = 48·m/(2·m) = 24

The new acceleration of the object, a₂ = 24 m/s².

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