What is the average acceleration of a rocket that travels 400m in 5s if it starts from rest?

Physics

1 answer:

Pavel [41]3 years ago

4 0

Answer:

Explanation:

We want to find the acceleration based on the given data

Given

distance s=400m

time t= 5s

u= 0m/s since it started from rest

We apply the following expression

s=ut+1/2at^2

substituting we have

400=0*5+1/2*a(5)^2

400=25a/2

cross multiply

25a=400*2

25a=800

divide both sides by 25 we have

a=800/25

a=32m/s^2

The acceleration is 32m/s^2

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The mass of block B is twice the mass of block A, while the mass of the pulley is equal to the mass of block A. The blocks are l

marshall27 [118]

Answer:

C)the right cord pulls on the pulley with greater force than the left cord

Explanation:

As we can see the figure that B is connected to the right string while A is connected to the left string

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similarly for block A which will move upwards we can write the equation as

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now we know that pulley is also rotating so the tangential acceleration of the rope at the contact point with pulley must be same as that of acceleration of the blocks

so here pulley will rotate clockwise direction

So tension in the right string must be more than the left string

So correct answer will be

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