Answer:
<h2>0.39m/s^2</h2>
Explanation:
Step one:
given data
mass m= 300kg
applied force F= 1000N
coefficient of friction μ= 0.3
Step two:
The net force Fn= applied force-friction force
Fn=F-F1
F1= limiting force
F1=μ*m*g
F1=0.3*300*9.81
F1=882.9N
the Net force= 1000-882.9
Fn=117.1N
Step three:
we know that
F=ma
Fnet=ma
a= Fnet/m
a=117.1/300
a=0.39m/s^2
1cathode rays plural : the high-speed electrons emitted in a stream from the heated cathode of a vacuum tube
2: a stream of electrons emitted from the cathode of a vacuum tube —usually used in plural
He should choose the room that’s 15 F.
-5 C = 23 F
Meaning that 15 F is below -5 C and 25 F is not.
Answer:
F = 20.07 μN
Explanation:
given,
intensity of sunlight = 667 W/m²
area of surface = 9.03 m²
speed of light = 3 x 10⁸ m/s
force = ?
we know
force =
force =
F = 20.07 x 10⁻⁶ N
F = 20.07 μN