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vekshin1
3 years ago
12

After the driver first notices the obstacle, the car moves uniformly for a time interval t1−t0=t before the brakes are applied.

Find the distance x1−x0 covered by the car in the time interval before the brakes are applied and after the driver sees the obstacle.
Physics
1 answer:
loris [4]3 years ago
3 0

Answer:

V(t1-t0)

Explanation:

Moving 'uniformly' means constant velocity (speed). the formula for constant speed motion is V = \frac{distance}{time} =( change in position/ change in time)

where,

                  V is speed

given in the statement :

change in time = t =  t1-t0

let the constant speed be ' V '

disance = X = X1-X0

applying the above mentioned formula: V = \frac{X}{t}

V = X/t

X = Vt

the distance X1-X0 = Vt =V(t1-t0)

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Answer:

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Let radius of wheel be R

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R⁴ = 2 x 2.2538 x 10⁵ / πt d

= 4.5076 x 10⁵ / 3.14 x .1 x 7800

= 184

R= 3.683 m .

diameter = 7.366 m .

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2 years ago
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Answer:

14m/s

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Unknown:

Speed needed to keep the car on the curve = ?

Solution:

The centripetal acceleration is the inwardly directly acceleration needed to keep a body along a curved path.

 It is given as;

      a = \frac{v^{2} }{r}  

a is the centripetal acceleration

v is the speed

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  Now insert the parameters and find v;

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3 years ago
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4 0
2 years ago
The gnaphosid spider Drassodes cupreus has evolved a pair of lensless eyes for detecting polarized light. Each eye is sensitive
BartSMP [9]

Answer:

Part A

The intensity is  I = 618 W/m^2  

Part B

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Explanation:

From the question we are told that

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Now at initial state according the question the light  ray is perpendicular to the eye so it means that it is at 90° the eye

Now the first question is to obtain the intensity the first eye (the first in this case is the one focused on the light  )would detect when the head is rotated by 20°  its previous orientation

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Now the second  question is to obtain the intensity the first eye (the first eye  in this case is the one that is not  focused on  the light  )would detect when the head is rotated by 20°  its previous orientation

Now in this case the angle between the eye and the light is 90-20 = 70°

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                   I_1= 81.884 W/m^2

 

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