Answer: The density of the unknown metal is 7.86 g/ml.
Explanation:
Density is defined as the mass contained per unit volume.
Given : Mass of metal = 25.32 g
Volume of metal = volume of water displaced = (28.22 - 25.00) ml = 3.22 ml
Putting in the values we get:
Thus the density of the unknown metal is 7.86 g/ml
Answer:
Explanation:
Mass of F / Mass of S = 2.962/1 =2.962 X 32 / 32 = 94.78/32
Mass of F / Mass of S = 2.370 /1 = 2.370 X 32 / 32 = 75.84 /32
Mass of F /Mass of S = 3.555/1 = 3.555 x 32 / 32 = 113.76 / 32 .
Now constant mass of S that is 32 g reacts with different mass of F. They are as follows :
94.78 g , 75.84 g , and 113.76 g
Their ratio = 94.78 : 75.84 : 113.76
divide them by 19
their ratio = 5 : 4 : 6
So these data are consistent with law of multiple proportion.
<u>Answer:</u> The volume of concentrated solution required is 9.95 mL
<u>Explanation:</u>
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
pH = 0.70
Putting values in above equation, we get:
![0.70=-\log[H^+]](https://tex.z-dn.net/?f=0.70%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=10^{-0.70}=0.199M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-0.70%7D%3D0.199M)
1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.
Molarity of nitric acid = 0.199 M
To calculate the volume of the concentrated solution, we use the equation:

where,
are the molarity and volume of the concentrated nitric acid solution
are the molarity and volume of diluted nitric acid solution
We are given:

Putting values in above equation, we get:

Hence, the volume of concentrated solution required is 9.95 mL
B. climate
this is because it influences the speed of chemical reactions in the soil