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Fed [463]
4 years ago
12

Which statement compares you tractive forces that hold particles together​

Chemistry
1 answer:
kolezko [41]4 years ago
4 0

Answer:

The answer is Ionic and covalent binding produces compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.

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4 years ago
Read 2 more answers
What is the mass in grams of 1.50 X 1023 molecules of NaOH?
avanturin [10]

Answer:

a. 10.0 g

Explanation:

The molar mass of NaOH is 39.997 grams which was calculated by adding the molar mass of Sodium, Oxygen, and Hydrogen 22.990 + 15.999 + 1.008 = 39.997. But before we do anything with this number we must first convert 1.50 * 10^{23} molecules to moles. We can do this by dividing by Avogadro's number or 6.022*10^{23}  ( \frac{1.50*10^{23}}{6.022*10^{23}} = 0.24909 moles). We then convert moles to grams by multiplying by the molar mass of NaOH, (0.24909 * 39.997 = 9.96 grams). This is almost exactly 10 and the margin of error is likely due to the original numbers not being precise enough.

5 0
4 years ago
10.0 Points 36 grams of water vapor takes up how many liters at room temperature and pressure (293 K and 100 kPa)?
AVprozaik [17]

100 kpa is correct

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8 0
4 years ago
H2SO4 + 2NaOH → 2H2O + Na So.
gayaneshka [121]

Answer:

2 mol H

Explanation:

For every 2 mol of NaOH, we're reacting 2 mol of H2O. In order to figure out how many mol of H are needed, it needs to be set up stochiometrically. Starting off with the given value, 1 mol of NaOH, we can then make a mol to mol ratio. For 2 mol of NaOH, we have 2 mol of H2O. For every 2 mol of H2O, we have 4 mol of H (this is because we are multiplying the coefficient by the subscript: 2 × 2). Now, we can solve for our answer.

1 mol NaOH × (2 mol H₂O / 2 mol NaOH) × (4 mol H / 2 mol H₂O)

= 2 mol H

Thus, we get 2 mol of H are needed to completely react 1 mol of NaOH.

7 0
4 years ago
I learned that ____is a substances used to dissolve a ______. Its is of the _____amount. There are substances that can be dissol
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1 solute

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8 0
3 years ago
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