Answer: True
Explanation: Specific Gravity of a body, also called its Relative Density, is the ratio of the density of that body to the density of a reference material (usually water).
With the Mathematics done right, it is evident that the specific gravity of a body would be equal to the ratio of mass/weight of the body to the mass/weight of an equal volume of water.
S.G = (Density of body)/(Density of water)
Density of Body = (mass/weight of body)/(volume of body)
Density of water = (mass/weight of water)/(volume of water)
If volume of Body = Volume of water, then,
S.G = (Mass/Weight of body)/(Mass/Weight of equal volume of water)
Proved!!
D.) There must be an equal number of atoms of each element on both sides of the equation
Answer:
We can solve this by the method of which i solved your one question earlier
so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372
which is almost = 41.26 moles
so to get one mole of C12H25NaSO4 we need one mole of C12H26O
so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O
so the mass of C12H26O = 41.26× its molar mass
C12H26O = 41.26×186.34
= 7688.38 gm!!
so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!
Again i d k wether it's right or wrong but i tried my best hope it helped you!!
Answer:
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First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2 so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄ ⇄ H⁺ + HC₂O₄⁻
0.0356 M 0 0
0.0356 - x x x
Ka1 =
![\frac{[H^+][HC2O4^-]}{[H2C2O4]}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BH%5E%2B%5D%5BHC2O4%5E-%5D%7D%7B%5BH2C2O4%5D%7D%20)
= x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6
