Answer:
34,6g of (NH₄)₂SO₄
Explanation:
The boiling-point elevation describes the phenomenon in which the boiling point of a liquid increases with the addition of a compound. The formula is:
ΔT = kb×m
Where ΔT is Tsolution - T solvent; kb is ebullioscopic constant and m is molality of ions in solution.
For the problem:
ΔT = 109,7°C-108,3°C = 1,4°C
kb = 1.07 °C kg/mol
Solving:
m = 1,31 mol/kg
As mass of X = 600g = 0,600kg:
1,31mol/kg×0,600kg = 0,785 moles of ions. As (NH₄)₂SO₄ has three ions:
0,785 moles of ions×
= 0,262 moles of (NH₄)₂SO₄
As molar mass of (NH₄)₂SO₄ is 132,14g/mol:
0,262 moles of (NH₄)₂SO₄×
= <em>34,6g of (NH₄)₂SO₄</em>
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I hope it helps!
A locating agent is needed in an experiment to separate amino acids by chromatography as it helps to analyze colorless substances on paper.
<h3>What is chromatography?</h3>
Chromatography is an analytical method frequently used to separate a chemical mixture into its components, allowing for in-depth analysis of each component.
There are many different types of chromatography including liquid, gas, ion-exchange, and affinity chromatography, but they all use the same basic principle.
<h3>What is the use of a locating agent in Chromatography?</h3>
In paper chromatography, colorless compounds are examined using a locating agent.
It is a chemical that combines with colorless substances to produce colorful compounds that are easy to see for analysis. Ninhydrin spray is an example of a locating agent of this type.
Thus, a locating agent is used in an experiment to separate amino acids by chromatography as it helps in determining colorless substances on paper.
Learn more about chromatography:
brainly.com/question/11960023
#SPJ9
Answer:
what are the answers?
Explanation:
Probably going to be c for this, until the answers you choose are shown. very very sorry :c
Answer:
The electronic configuration that are incorrectly written is 1s²2s³2p⁶, 4s²3d¹⁰4p⁷, 3s¹ and 2s²2p⁴.
Explanation:
The electronic configuration of the elements corresponds to how all the electrons of an element are arranged in energy levels and sub-levels.
There are 7 energy levels —from 1 to 7— whose sublevels are described as s, p, d and f.
All electronic configurations begin with the term "1s" —corresponding to the sublevel s of level 1— so 4s²3d¹⁰4p⁷, 3s¹ and 2s²2p⁴ are incorrectly written. In addition, 4s²3d¹⁰4p⁷ is written incorrectly because is impossible to jump from the sublevel "s" to the sublevel "d" —which is found from level 3 and up— without passing through the sublevel "p".
In the case of 1s²2s³2p⁶, the wrong thing is that the sublevel "s" can only hold two electrons, not three.
The other options are correctly written.
