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chubhunter [2.5K]
3 years ago
5

In aqueous solution the Ni2" ion forms a complex with four ammonia molecules. Write the formation constant expression for the eq

uilibrium between the hydrated metal ion and the aqueous complex. Under that, write the balanced chemical equation for the first step in the formation of the complex K,=________.
Chemistry
1 answer:
777dan777 [17]3 years ago
5 0

Answer:

The correct equation is "\frac{[Ni(H_2O)_3 (NH_3)]^{2+}}{[Ni(H_2O)_4]^{2+} [NH_3]}".

Explanation:

According to the question,

Throughout an aqueous solution, Ni^{2+} exist as [Ni(H_2O)_4]^{2+}

So,

⇒ [Ni(H_2O)_4]^{2+} + 4NH_3 \rightleftharpoons [Ni(NH_3)_4]^{2+} + H_2O

⇒ K_f = \frac{[Ni(NH_3)_4]^{2+}}{[Ni(H_2O)_4^{2+}] [NH_3]^4}

Here, we have excluded [H_2O] as concentration of water will be const.

Now,

This formation of [Ni(NH_3)_4]^{2+} proceeds via several steps,

Step 1:

⇒ [Ni(H_2O)_4]^{2+}+NH_3 \rightleftharpoons [Ni(H_2O)_3 (NH_3)]^{2+} + H_2O

⇒ K_1 = \frac{[Ni(H_2O)_3 (NH_3)]^{2+}}{[Ni(H_2O)_4]^{2+} [NH_3]}

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Answer:

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

Explanation:

Given data:

Atomic mass of silicon= ?

Percent abundance of Si-28 = 92.21%

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Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)+(abundance of 2nd isotope × its atomic mass)  / 100

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Average atomic mass =  2580.04 +136.21+92.61 / 100

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3 years ago
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Answer:

density=1.8x10^{-3}g/mL

Explanation:

Hello,

Considering the ideal equation of state:

PV=nRT

The moles are defined in terms of mass as follows:

n=\frac{m}{M}

Whereas M the gas' molar mass, thus:

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Now, since the density is defined as the quotient between the mass and the volume, we get:

P=\frac{m}{V} \frac{RT}{M}

Solving for m/V:

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Answer:

38 : 25

Explanation:

First thing's first, we have to confirm if the reaction is indeed balanced.

The equation of the reaction is given as;

C25H52 + 38 O2 → 25 CO2 + 26 H2O

From the reaction, 38 moles of O2 produces 25 moles of CO2

The ratio is given as;

38 : 25

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