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Aleksandr-060686 [28]
3 years ago
6

Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They

determine that a netforce of E causes a cart with a mass of M to accelerate at 48 cm/s/s. What is the acceleration value of a cart with....... Jsons DO a) A mass of M when acted upon by a net force of 2F? (2) Up = 0 b) A mass of 2M when acted upon by a net force of F? (2) c) A mass of 2M when acted upon by a netforce of 2F? (2) D-27 d) A mass of 4M when acted upon by a net force of 2F? (2) fret 3. e) A mass of 2M when acted upon by a netforce of 4F? (2) (30) -8,76 m.52 1000 2 (0,48) a thez 0240 P = my Eper verere 5 ma​
Engineering
1 answer:
const2013 [10]3 years ago
8 0

Answer:

manda a senha senha do brainly bloquearam os amigos bloquearam os amigos e você vai ver o meu perfil você vai ver o meu perfil você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo uma academia de lima e você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo uma academia de lima e você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo uma academia de lima e você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo uma academia de lima e

Explanation:

Marcar como melhor porfavo

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Answer:

solution in the picture attached

Explanation:

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3 years ago
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Answer:

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8 0
3 years ago
A circuit has a source voltage of 15V and two resistors in series with a total resistance of 4000Ω .If RI has a potential drop o
anastassius [24]

Answer:

1500Ω

Explanation:

Given data

voltage = 15 V

total Resistance = 4000Ω

potential drop V = 9.375 V

To find out

R2

Solution

we know R1 +R2 = 4000Ω

So we use here Ohm's law to find out current I

current = voltage / total resistance

I = 15 / 4000 = 3.75 × 10^{-3} A

Now we apply Kirchhoffs Voltage Law for find out R2

R2 = ( 15 - V ) / current

R2 = ( 15 - 9.375 ) / 3.75 × 10^{-3}

R2 = 1500Ω

6 0
3 years ago
The extruder head in a fused- deposition modeling setup has a diameter of 1.25 mm (0.05 in) and produces layers that are 0.25mm
Angelina_Jolie [31]

Answer:

The time taken will be "1 hour 51 min". The further explanation is given below.

Explanation:

The given values are:

Number of required layers:

= \frac{38}{0.25}

= 152 \ layers

Diameter (d):

= 1.25 mm

Velocity (v):

= 40 mm/s

Now,

The area of one layer will be:

= 38\times 38 \ mm^2

= 1444 \ mm^2

The area covered every \second will be:

= d\times v

= 1.25\times 40

= 50 \ mm^2

The time required to deposit one layer will be:

= \frac{1444}{50}

= 28.88 \ sec

The time required for one layer will be:

= 15 \ sec

∴ Total times required for one layer will be:

= 15+28.88

= 43.88 \ sec

So,

Number of layers = 152

Therefore,

Total time will be:

= 152\times 43.88

= 6669.76 \ sec

= 1 \ hour \ 51 \ min

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4 years ago
For every 3 packages that Marcella wraps she uses 1/2 of a roll of wrapping paper if she uses 2 1/2 rolls of wrapping paper how
hram777 [196]
She wrapped 5 packages
6 0
3 years ago
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