Answer:
solution in the picture attached
Explanation:
Answer:
Answer to both the parts A and B are provided in the word document attached.
Explanation:
The explanation of the programs is provided in the attached file along with the screenshot of ATM application output.
Answer:
1500Ω
Explanation:
Given data
voltage = 15 V
total Resistance = 4000Ω
potential drop V = 9.375 V
To find out
R2
Solution
we know R1 +R2 = 4000Ω
So we use here Ohm's law to find out current I
current = voltage / total resistance
I = 15 / 4000 = 3.75 ×
A
Now we apply Kirchhoffs Voltage Law for find out R2
R2 = ( 15 - V ) / current
R2 = ( 15 - 9.375 ) / 3.75 ×
R2 = 1500Ω
Answer:
The time taken will be "1 hour 51 min". The further explanation is given below.
Explanation:
The given values are:
Number of required layers:
= 
= 
Diameter (d):
= 1.25 mm
Velocity (v):
= 40 mm/s
Now,
The area of one layer will be:
= 
= 
The area covered every \second will be:
= 
= 
= 
The time required to deposit one layer will be:
= 
= 
The time required for one layer will be:
= 
∴ Total times required for one layer will be:
= 
= 
So,
Number of layers = 152
Therefore,
Total time will be:
= 
= 
= 