Answer:
volumetric flow rate = 
Velocity in pipe section 1 = 
velocity in pipe section 2 = 12.79 m/s
Explanation:
We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.
The density of water is = 997 kg/m³
density = mass/ volume
since we are given the mass, therefore, the volume will be mass/density
25/997 = 
volumetric flow rate = 
Average velocity calculations:
<em>Pipe section A:</em>
cross-sectional area =

mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)

<em>Pipe section B:</em>
cross-sectional area =

mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)

A continuous time-varying 1-D signal is sampled by narrow sampling pulses at a regular rate fr = 1/T, which must be at least twice the bandwidth of the signal. At first, it may be somewhat surprising that the original waveform can be reconstructed exactly from a set of discrete samples.
Answer:
a) the flow under full capacity is q₂= 1.334 ft³/s
b) the velocity would be v= 3.793 ft/s
Explanation:
a) Since the pipe has 8 inches in diameter but 4 are covered with water flow ( half of a circle in area=A₁) , q₁=0.662 ft³/s then
q₁=A₁*v
then for the same velocity v but area A₂=2*A₁
flow under full capacity= q₂ = A₂*v= 2*A₁*v= 2*q₁=2*0.662 ft³/s= 1.334 ft³/s
b) when flowing at a depth of 4 inches
A₁= (1/2)*(π*D²/4) = π* (1/8)*(8 in)² = 8π in² * (1 ft²/ 144 in²) = π/18 ft² = 0.1745 ft²
then
v=q₁/A₁ = 0.662 ft³/s/0.1745 ft²= 3.793 ft/s
v= 3.793 ft/s
Answer:
(A) Fourier Analysis
Explanation:
Fourier Analysis
It is the form of study of the way a general functions can be represented via the sum of the simple trigonometric functions .
It is named after Joseph Fourier , who represented a function as a sum of its trigonometric functions and it simplifies the study of the heat transfer .
Hence ,
The technique for resolving the complex repetitive waveforms into the sine or the cosine waves and the DC component is known as the Fourier Analysis .