Answer:
velocity = 62.89 m/s in 58 degree measured from the x-axis
Explanation:
Relevant information:
Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.
Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.
Before collision Momentum of A = 1000 x 100 =
kg - m/s in the right direction.
Before collision Momentum of B = 2000 x 80 = 1.6 x
kg - m/s in upward direction.
Mass of System of after collision = 1000 + 2000 = 3000 kg
Now applying the Momentum Conservation, we get
Initial momentum in right direction = final momentum in right direction =
And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x
So,
=
m/s
and
m/s
Therefore, velocity is = 
= 
= 62.89 m/s
And direction is
tan θ =
= 1.6
therefore, 
=
from x-axis
<h2>
Answer:</h2>
The event horizon is the surface of a black hole, it is the border of space-time in which the events on one side of it can not affect an observer on the other side.
That is, at this border also called "point of no return", nothing can escape (not even light) and no event that occurs within it can be seen from outside.
The relevant equation to use here is:
y = v0 t + 0.5 g t^2
where y is the vertical distance, v0 is initial velocity =
0, t is time, g = 9.8 m/s^2
y = 0 + 0.5 * 9.8 * 3^2
<span>y = 44.1 meters</span>
Answer: Well you didn't give any answers so my guess would be it depends how much force you put into it and where you throw it.
Explanation: