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yKpoI14uk [10]
3 years ago
12

It takes Priti 4 hours to drive from Ashdown to Bridgeton at an average speed of 50 mph. She then drives 30 miles from Bridgeton

to Carton at an average speed of 40 mph. Assuming Priti doesn't stop, what is her average speed from Ashdown to Carton to 1 dp?
Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

Her average speed from Ashdown to Carton is approximately 48.4 mph

Step-by-step explanation:

The time and speed of the motion of Priti are as follows;

The time it takes Priti to drive from Ashdown to Bridgeton, t₁ = 4 hours

The average speed she drove from Ashdown to Bridgeton = 50 mph

The distance she drove from Bridgeton to Carton, d₂ = 30 miles

Her average speed from Bridgeton to Carton = 40 mph

The distance from Ashdown to Bridgeton, d₁ = 50 mph × 4 hours = 200 miles

The time it takes Priti to drive from Bridgeton to Carton, t₂ = 30 miles/(40 mph) = 0.75 hour

Average velocity, v_{ave} = (Total distance traveled, Δd)/(Total time, Δt)

Δd = d₁ + d₂, Δt = t₁ + t₂

Δd = 200 miles + 30 miles = 230 miles

Δt = 4 hours + 0.75 hour = 4.75 hours

∴ The average velocity, v_{ave} = (230 miles)/(4.75 hours)

∴ v_{ave} = (920/19) mph

Her average speed from Ashdown to Carton, rouded to 1 d,p, v_{ave} ≈ 48.4 mph

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Answer:

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Step-by-step explanation:

Expand f(x) = a(x + b)² + c and compare coefficients of like terms, that is

a(x + b)² + c ← expand (x + b)² using FOIL

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= ax² + 2abx + ab² + c

Compare like terms with f(x) = 2x² - 12x + 10

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2ab = - 12, substitute a = 2

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18 + c = 10 ( subtract 18 from both sides )

c = - 8

Then a = 2, b = - 3, c = - 8

 

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Francis works at Carlos Bakery and is making cookie trays. She has 48 chocolate chip cookies, 64 rainbow cookies, and 120 oatmea
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The number of cookies and trays are illustrations of greatest common factors.

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The given parameters are:

\mathbf{Chocolate\ chip=48}

\mathbf{Rainbow=64}

\mathbf{Oatmeal=120}

<u>(a) The number of trays</u>

To do this, we simply calculate the greatest common factor of 48, 64 and 120

Factorize the numbers, as follows:

\mathbf{48 = 2 \times 2 \times 2 \times 2 \times 3}

\mathbf{64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2}

\mathbf{120 = 2 \times 2 \times 2 \times 3 \times 5}

So, the GCF is:

\mathbf{GCF= 2 \times 2 \times 2}

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Hence, the number of tray is 8

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We have

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Divide each cookie by the number of trays

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Hence, 6 chocolate chips, 8 rainbows and 15 oatmeal cookies would fit each tray

Read more about greatest common factors at:

brainly.com/question/11221202

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