Explanation:
The word equation for the burning of a candle is wax plus oxygen yields carbon dioxide and water. This is an exothermic reaction that produces both light and heat.
The fuel for a burning candle is the wax. There are many different types of wax with a corresponding number of chemical formulas, but they are all hydrocarbons. Hydrocarbons are molecules made from hydrogen and carbon.
Burning the wax pulls the hydrogen and carbon in the wax apart and recombines them with oxygen from the atmosphere. This is an oxidation reaction. The resulting carbon dioxide and water are gases that disperse in the air.
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The energy range expected is 6.6 × 10^-19 J < E < 7.33 × 10^-19 J
The energy of the photon is given by;
E = hc/λ
E = energy of the photon
h = Plank's constant
c = speed of light
λ = wavelength of light
For the upper boundary range;
E = ?
h = 6.6 × 10^-34 Js
c = 3 × 10^8 m/s
λ = 270 × 10^-9
E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 270 × 10^-9
E = 7.33 × 10^-19 J
For the lower range;
E = ?
h = 6.6 × 10^-34 Js
c = 3 × 10^8 m/s
λ =300 × 10^-9
E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 300 × 10^-9
E = 6.6 × 10^-19 J
Hence, the energy range 6.6 × 10^-19 J < E < 7.33 × 10^-19 J
Learn more: brainly.com/question/24857760
The given solution is a mixture of 
and 
. It acts as a buffer as it is a combination of the weak acid 
and it's conjugate base 
.
![[Acid] = [HCO_{3}^{-}]=1.0 M](https://tex.z-dn.net/?f=%5BAcid%5D%20%3D%20%5BHCO_%7B3%7D%5E%7B-%7D%5D%3D1.0%20M)
![[Base] =[CO_{3}^{2-}]=0.1 M](https://tex.z-dn.net/?f=%5BBase%5D%20%3D%5BCO_%7B3%7D%5E%7B2-%7D%5D%3D0.1%20M)
pH of the buffer solution can be calculated from Hendersen-Hasselbalch equation as below:
![pH=pK_{a}+log\frac{[CO_{3}^{2-}]}{[HCO_{3}^{-}]}](https://tex.z-dn.net/?f=pH%3DpK_%7Ba%7D%2Blog%5Cfrac%7B%5BCO_%7B3%7D%5E%7B2-%7D%5D%7D%7B%5BHCO_%7B3%7D%5E%7B-%7D%5D%7D)
pH = 10.33+(-1)
= 9.33
