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3 years ago

15

Ignore this hvhvivguouv

2 answers:

kakasveta [241]3 years ago

5 0

Answer:

hgcxfzdfdgxhcjvhkbjlkjkhjkgfgfg

Explanation:

yw :]

aalyn [17]3 years ago

3 0

Answer:

Umm sorry I don't know how to answer this question

Explanation:

sorry can't answer

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Why is magnetic force a non contact force?

lianna [129]

Bcoz when you place a magnet close enough the magnet attracts or repals without any other fore we dont touch the magnet so it is non contact

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3 years ago

GREYUIT [131]

Answer:

it comes from your knowledge and the information you have to get the reason why that is the answer so you are putting together things that you already know what the new information you have

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3 years ago

Consider two soap bubbles with radius r1 and r2 (r1 <r2) connected via a valve. What happens if we open the valve

Sedaia [141]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The pressure difference of the first bubble is $\Delta P _1 =10 J/m^3$

The pressure difference of the second bubble is $\Delta P _2 =20 J/m^3$

The pressure difference on the second bubble is higher than that of the first bubble so when the valve is opened pressure from second bubble will cause air to flow toward the first bubble making is bigger

Explanation:

From the question we are told that

The radius of the first bubble is $r_1 = 10 \ mm=0.01 \ m$

The radius of the second bubble is $r_2 = 5 \ mm = 0.005 \ m$

The surface tension of the soap solution is $s = 25 \ mJ/m^2 = 25*10^{-3} J/m^2$

Generally according to the Laplace's Law for a spherical membrane the pressure difference is mathematically represented as

$\Delta P = \frac{4 s}{R}$

Now the pressure difference for the first bubble is mathematically evaluated as

$\Delta P _1 = \frac{4 s}{r_1}$

substituting values

$\Delta P _1 = \frac{4 *25 *10^{-3}}{0.01}$

$\Delta P _1 =10 J/m^3$

Now the pressure difference for the second bubble is mathematically evaluated as

$\Delta P _2 = \frac{4 s}{r_1}$

$\Delta P _2 = \frac{4 *25 *10^{-3}}{0.005}$

$\Delta P _2 =20 J/m^3$

3 0

3 years ago

A weightlifter lifts a set of weights a vertical distance of 2 meters. If a constant net force of 350 N is exerted on the weight

o-na [289]

Answer:

The work done by the weightlifter, W = 700 J

The power of the weightlifter, P = 350 watts

Explanation:

A weightlifter lifts a set of weights a vertical distance, s = 2 m

The force exerted to lift the weight, F = 350 N

The work done by the body is defined as the product of the force applied by the body to the displacement it caused.

W = F x s

= 350 N x 2 m

= 700 J

The work done by the weightlifter, W = 700 J

The time taken by the weightlifter to lift the weight, t = 2 s

The power is defined as the rate of body to do work. It is given by the equation,

P = W / t

= 700 J / 2 s

= 350 watts

Hence, the power of the weightlifter, P = 350 watts

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3 years ago

Oak trees make many acorns that can become new oak trees what is this an example of

Kisachek [45]

Reproduction! hope this helps u.

4 0

4 years ago

Read 2 more answers