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2 years ago

HELPPP!!! i need to know this asap!!

Mathematics

1 answer:

Ksivusya [100]2 years ago

5 0

Answer:

The first option

(-10, -7)

Step-by-step explanation:

Also I really like your pfp <33

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GarryVolchara [31]

Answer:

Step-by-step explanation:

the green cylinder is 20 $\pi$

while the purple cone is 18 $\pi$

which do you think is more ? :)

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2 years ago

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A TV company when purchasing thousands electronic components apply this sampling plan: randomly select 15 of them and then accep

katrin [286]

<h2>Answer with explanation:</h2>

According to the Binomial probability distribution ,

Let x be the binomial variable .

Then the probability of getting success in x trials , is given by :

$P(X=x)=^nC_xp^x(1-p)^{n-x}$ , where n is the total number of trials or the sample size and p is the probability of getting success in each trial.

As per given , we have

n = 15

Let x be the number of defective components.

Probability of getting defective components = P = 0.03

The whole batch can be accepted if there are at most two defective components. .

The probability that the whole lot is accepted :

$P(X\leq 2)=P(x=0)+P(x=1)+P(x=2)\\\\=^{15}C_0(0.03)^0(0.97)^{15}+^{15}C_1(0.03)^1(0.97)^{14}+^{15}C_2(0.03)^2(0.97)^{13}\\\\=(0.97)^{15}+(15)(0.03)^1(0.97)^{14}+\dfrac{15!}{2!13!}(0.03)^2(0.97)^{13}\\\\\approx0.63325+0.29378+0.06360=0.99063$

∴The probability that the whole lot is accepted = 0.99063

For sample size n= 2500

Expected value : $\mu=np= (2500)(0.03)=75$

The expected value = 75

Standard deviation : $\sigma=\sqrt{np(1-p)}=\sqrt{2500(0.03)(0.97)}\approx8.53$

The standard deviation = 8.53

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2 years ago

Normal probability plots indicate that the sample data come from normal populations. Are the requirements to use the one-way AN

Mrrafil [7]

Answer:

No it is not satisfied

Step-by-step explanation:

The one-way ANOVA is used to measure whether the difference between the means of two independent groups are statistically significant.

For it to be satisfied, there has to be one independent variable which is categorical and one dependent variable. The dependent variable on its own has to be a continuous variable

The assumptions are:

1. Equal variance between population

2. Independence between observations

3. The random samples have to be gotten from a normal population.

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3 years ago

What is the total weight of the bunches of bananas that weigh 1 3\4 pounds

Lisa [10]

If it weighs 1 3/4 lb’s then that’s it’s total weight…

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2 years ago

What is the sum of .5 and .3 repeating

vovangra [49]

.8 repeating. I believe is this answer.

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3 years ago

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