Answer:
10.0 g of AgI will produce 5.28 g of Ag₂S
Explanation:
The balanced equation of the reaction is given below:
2AgI + Na₂S ----> Ag₂S + 2NaI
From the equation of reaction, 2 moles of AgI produces 1 mole of Ag₂S
The moles of a substance is related to its mass by a quantity known as molar mass which is defined as the mass of one mole of that substance.
Molar mass of AgI = (108 + 127) g = 235 g
Molar mass of Ag₂S = (108 × 2 + 32) g= 248 g
Mass of 2 moles of AgI = 2 × 235 g = 470 g
470 g of AgI produces 248 g of Ag₂S
10 g of AgI will produce 248 /470 × 10 g of Ag₂S = 5.28 g
Therefore, mass of Ag₂S produced = 5.28 g
