Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = <span>pi\over4*d^2=pi\over4*0.3^2=0.07 m^2
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Answer:
-4/7
Explanation:
Given the following
A=4i-10j and B= 7i+5j
A+ bB = 4i-10j + (7i+5j)b
A+ bB = 4i-10j + 7ib+5jb
A+ bB =
The vector along the x-axis is expressed as i + 0j
If the vector A+ bB is pointing in the direction of the x-axis then;
Hence the value of b is -4/7
Answer:
Assuming air resistance is negligible, all of the potential energy that the object has at the top of the ramp is converted into kinetic energy by the time it gets to the bottom of the ramp. This is because no matter what path the object takes to move the 5m vertically (ie. falling straight down v. sliding on the ramp), gravity does the same amount of work on it.
Thus, calculate the total amount of potential energy at the top of the ramp:
Ep=mgh
Ep=4(9.81)5
Ep=196.2 Joules
Because all of this potential energy is converted into kinetic energy in the object by the bottom of the ramp, the object hits the spring with 196.2J of energy.
By using the formula for elastic potential energy, you can calculate exactly how far the spring compresses.
196.2=(1/2)k(x^2)
392.4=(350)(x^2)
1.1211=x^2
sqrt(1.1211)=x
x=1.059m
As for the last part of the question, after the object compresses the spring fully and stops momentarily, the spring converts it's elastic potential energy back into kinetic energy in the object and pushes it away again.
Explanation:
You can apply conservation of angular momentum since there is no external torque on the system. I have done that in the picture below. Remember to always convert to correct units. Just plug numbers in on what I’ve given you and you should get the final angular speed