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koban [17]
3 years ago
8

a car has a velocity of 10ms-1. it accelerates at 0.2 ms-2 for half minute find the total distance travelled and final velocity

of car.​
Physics
1 answer:
Readme [11.4K]3 years ago
5 0

Answer:

Final velocity = 16 m/s

Total distane travelled = 390 m

Explanation:

We can use equation of motion to solve this:

v = u + at \\ v = 10 + 0.2(30) \\ v = 16 {ms}^{ - 1}

s = ut +  \frac{1}{2} a {t}^{2}  \\ s = 10(30) +  \frac{1}{2} (0.2) {(30)}^{2}  \\ s = 390m

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Describe the motion of the object in Graph B of figure 11-2.
kupik [55]

Answer : The motion of the object is, non-uniform

Explanation :

Uniform motion : It is defined as the movement of an object along a straight line with constant speed.  It travels equal distances in equal time interval.

The average speed of an object is similar to the actual speed of an object.  The distance-time graph shows a straight line.

Non-uniform motion : It is defined as the movement of an object along a straight line with variable speed.  It travels unequal distances in equal time interval.

The average speed of an object is different to the actual speed of an object.  The distance-time graph shows a curved line.

The given graph B is a non-uniform motion graph.

Hence, the motion of the object is, non-uniform


4 0
3 years ago
Read 2 more answers
an object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m. determine the image height (in cm)
Juli2301 [7.4K]

Given :

An object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m.

To Find :

the image height (in cm).

Solution :

By lens formula :

\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}

Here, u = - 100 cm

f =  150 cm

\dfrac{1}{v} - \dfrac{1}{-100} = \dfrac{1}{150}\\\\v = - 300 \ cm

Now, magnification is given by :

m = \dfrac{v}{u} = \dfrac{h_i}{h_o}\\\\h_i = \dfrac{300}{100}\times 1\\\\h_i = 3 \ m

Therefore, the image height is 3 m or 300 cm.

5 0
3 years ago
How do magnetic stripes show the history of earth's magnetic field?
Mama L [17]
If i could heat a piece of iron so that it melted, and then held a magnet close to the molten iron and then let the iron cool to room temperature, you could use a microscope to look at the iron and tell that a magnet had been present during cooling. you could even tell if it was the north or south pole of the magnet that i held close to the molten iron.

Magma/lava contains a lot of molten iron so that when it erupts from a volcano and cools, the magnetic field of the earth leaves an imprint in it, just like the cooling iron from above. From this imprint we can tell the strength of the magnetic field and also which direction the north and south poles were at the time.
3 0
3 years ago
Why can't we say a measurement tool is accurate?
sashaice [31]

There are various reasons why a measurement tool cannot be accurate. One of them is thermal contraction and expansion varies according to seasons.

<h3>What are Accuracy and Precision?</h3>

There are two ways to assess observational error: accuracy and precision. Precision measures how closely two measurements are to one another, whereas accuracy measures how close a group of measurements is to its actual value. In other words, precision is a measure of statistical variability and a description of random errors.

We can say that a tool can be precise, but it cannot be accurate. There are various reasons behind that, some of them are :

  • It may not be calibrated properly. If there are no reliable standards to use for calibration, this may occur.
  • Perhaps it strayed. This is why electronic scales include a tare function—they are terrible in this area.
  • Perhaps the measurements are not linear. Our calipers might have been quite precise at the 2-inch standard, where they were calibrated, but inaccurate at other dimensions.
  • Temperature is one environmental component that the instrument might be sensitive to. These effects might be compensated for, but the compensation might not be ideal. This issue affects both dissolved solids meters and picometers.

These are some of the reasons due to which measurement tool cannot be accurate.

To get more information about Accuracy and Precision :

brainly.com/question/15276983

#SPJ1

7 0
2 years ago
A)If the rms value of the electric field in an electromagnetic wave is doubled, by what factor does the rms value of the magneti
Ghella [55]

A) The magnetic field doubles as well

The relationship between rms value of the electric field and rms value of the magnetic field for an electromagnetic wave is the following:

E_{rms}=cB_{rms}

where

E_rms is the magnitude of the electric field

c is the speed of light

B_rms is the magnitude of the magnetic field

From the equation, we see that the electric field and the magnetic field are directly proportional: therefore, if the rms value of the electric field is doubled, then the rms value of the magnetic field will double as well.

B) The intensity will quadruple

The intensity of an electromagnetic wave is given by

I=\frac{1}{2}c\epsilon_0 E_0^2

where

c is the speed of light

\epsilon_0 is the vacuum permittivity

E_0 is the peak intensity of the electric field

The rms value of the electric field is related to the peak value by

E_{rms}=\frac{E_0}{\sqrt{2}}

So we can rewrite the equation for the intensity as

I=c\epsilon_0 E_{rms}^2

we see that the intensity is proportional to the square of the rms value of the electric field: therefore, if the rms value of the electric field is doubled, the average intensity of the wave will quadruple.

7 0
3 years ago
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