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Stella [2.4K]
4 years ago
11

Hartman value profile

Physics
1 answer:
Grace [21]4 years ago
6 0
What is your question exactly? I'm confused?
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In a very busy off-campus eatery one chef sends a 201 g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter fro
Murrr4er [49]

Answer:

The correct answer is:

(A) to the left

(B) at speed -0.8725 m/s

Explanation:

The given values are:

Plate 1:

Mass,

m₁ = 201 g

Velocity,

v₁ = +1.79 m/s

Plate 2:

Mass,

m₁ = 335 g

Velocity,

v₁ = -2.47 m/s

According to the conservation of momentum, we get

⇒  m_1v_1+m_2v_2=(m_1+m_2)v

then,

⇒  v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

On substituting the values, we get

⇒     =\frac{201\times 1.79+335\times (-2.47)}{201+335}

⇒     =\frac{359.79-827.45}{536}

⇒     =\frac{-467.66}{536}

⇒     =-0.8725 (to the left)

3 0
3 years ago
Hii guys!! ~ i've comeback again!! could you please help me with an assignment?? i have a couple of i know questions!! thank you
Nimfa-mama [501]

Answer:

Speed = 10.24 m/s.

Explanation:

<u>Given the following data;</u>

Distance = 100m

Time = 9.77

To find her speed;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

Speed = \frac{distance}{time}

Substituting into the equation, we have;

Speed = \frac{100}{9.77}

<em>Speed = 10.24 meter per seconds. </em>

5 0
3 years ago
How do land and sea breeze work?
Studentka2010 [4]
 by the wind and air flow in the wind

7 0
4 years ago
A moving walkway at an airport has a speed v1 and a length L. A woman stands on the walkway as it moves from one end to the othe
bearhunter [10]

Answer:

t=L/V_1

Explanation:

<u>solution:</u>

Let E be an observer, and B a second observer traveling with velocity V_{BE}  as measured by E. If E measures the velocity of an object A as V_{AE}  then B will measure A velocity as

V_{AB} = V_{AE} -  V_{BE}  

Applied here,

the walkway (W) and the man (M) are moving relative to Earth (E}, the velocity of the man relative to the moving walkway is

V_{MW} = V_{ME} -  V_{WE}  

V_1=V_{WE},

V_2=V_{MW}

The time required for the woman, traveling at constant speed V_1 relative to the ground, to travel distance L relative to the ground is :

t=L/V_1

 

3 0
4 years ago
A lump of clay whose rest mass is 4 kg is travelling at three-fifths the speed of light when it collides head-on with an identic
Harman [31]

Answer:

mass of the composite lump is 10 kg

Explanation:

given data

mass = 4 kg

to find out

mass of composite lump

solution

we know energy is conserved so

so m1 = m2 = m0 that is 4kg

and

E(1) release+ E(2) release = E(1,2) rest

so γ(1)m(1)c² + γ(2)m(2)c²  = Mc²    ..........................1

that why here

|v(1)| = |v(2)| = 3/5 c        ......................2

and

γ = 1 / √(1 − v²/c²)           .......................3

put here v = 3 and c is 5

γ = 1 /√(1 − 9/25)

γ =  5/4

so

γ(1) = γ(2) = γ = 5/4  

so from equation 1

γ(1)m(1)c² + γ(2)m(2)c²  = Mc²

M = 2γm0

M = 2(5/4 )(4)

M = 10 kg

so mass of the composite lump is 10 kg

7 0
4 years ago
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