Answer:
Amount of salt needed is around 2.3*10³ g
Explanation:
The salt content in sea water = 3.5 %
This implies that there is 3.5 g salt in 100 g sea water
Density of seawater = 1.03 g/ml
Volume of seawater = volume of tank = 62.5 L = 62500 ml
Therefore, the amount of seawater required is:

The amount of salt needed for the calculated amount of seawater is:

<u>False</u> is the correct answer.
Answer:
Anyone should be able to read the lab report, repeat the experiment, and get the same results. This is important for scientists. ... They help the scientists know what has been done before and how it was performed. This can help them design experiments for their own research
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