1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
e-lub [12.9K]
2 years ago
9

Explain what is meant by the phrase 'the heat death of the universe."

Chemistry
2 answers:
jek_recluse [69]2 years ago
7 0

Answer:

hypothesis on the ultimate fate of the universe, which suggests the universe would evolve to a state of no thermodynamic free energy and would therefore be unable to sustain processes that increase entropy.

Explanation:

Vikki [24]2 years ago
6 0

Answer:

See explanation.

Explanation:

Are you literally posting your entire you chemistry homework on this site, one question at a time? Anyways, the heat death refers to the second law of thermodynamics and entropy. Heat is constantly flowing from warmer to cooler objects and never the other way around. This heat flow increases entropy, which is constantly increasing. The universe will eventually disperse all of its heat energy away to continuously increase entropy and reach a limit as the temperature reaches 0 K at which point all molecular motion will cease and so will the life of the universe.

You might be interested in
What is the effect of tap water, sea water, and rainwater on the rusting rate of iron?
UkoKoshka [18]

Answer:

The more acidic the solution the faster it rusts. More Na = more rust

Explanation:

4 0
3 years ago
An ideal gas is kept in a 10​-liter ​[L] container at a pressure of 2.5 atmospheres​ [atm] and a temperature of 310 kelvin​ [K].
Hatshy [7]

Answer:

5 L.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 10 L

Initial pressure (P1) = 2.5 atm

Final pressure (P2) = 5 atm

Final volume (V2) =.?

Since the temperature is constant, we shall apply the Boyle's law equation to determine the new volume of the gas. This can be obtained as follow:

P1V1 = P2V2

2.5 × 10 = 5 × V2

25 = 5 × V2

Divide both side by 5

V2 =25/5

V2 = 5 L

Thus, the new volume of the gas is 5 L

8 0
2 years ago
For the reaction A(g)
zubka84 [21]

Answer:

Yes

Explanation:

By definition, the equilibrium constanct, Kc, for the reaction A ⇒ 2B is

= [A]^1 / [B]^2

Substitute [A] = 4 and [B] = 2 in the equation,

[A]^1 / [B]^2

= 4^1 / 2^2

= 1

= Kc

So yes the reaction is at equilibrium.

6 0
2 years ago
For the following amino acids, draw a triangle around the amine group, draw a square around the carboxyl and circle the side gro
mylen [45]

hooc are carboxyl groups

your r or amino groups are those unique structures which have different atoms in them. your nh2 groups are your hydrogen atoms

4 0
3 years ago
Upon balancing the equation what is the smallest possible integers that goes in front O₂? HBr + O₂ ➞ H₂O + Br₂ *
Leokris [45]

Answer:

1

Explanation:

4 HBr + O2 → 2H 20 + 2Br 2

...............

7 0
2 years ago
Read 2 more answers
Other questions:
  • Which organism can reach 50 meters in size
    13·1 answer
  • The phase of matter can be changed by:
    10·2 answers
  • When an electron is removed the atoms charge changes to a what?
    9·1 answer
  • Which of the following is equal to 2.3 cm3?
    9·1 answer
  • Calculate the freezing temperature of the following solution of 0.50 M glucose (a covalent compound). Assume that the molality o
    14·1 answer
  • Consider four different samples: aqueous LiBr, molten LiBr, aqueous AgBr, and molten AgBr. Current run through each sample produ
    7·1 answer
  • Give the percent yield when 162.8 g of CO2 are formed from the reaction of excess amount of
    5·2 answers
  • Gold has a configuration of 1s22s22p63s23p63d104824p64d105525p645145d10651
    15·1 answer
  • A balloon is filled with helium gas has a volume of 1.0 L at a pressure of 1.0 atm. The
    10·1 answer
  • Balance the equations for the formation of cations from neutral atoms
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!