Only gas or vapor can be superheated. Use water as an example. Water at sea level boils at 212 degrees F. When heated to 212 degrees F, the molecules that make up water are moving at a high enough speed that they overcome the air pressure above the water. And for supercooled only liquids or solids can be supercooled for example Liquid water at sea level has a saturation (boiling) temperature of 212 degrees F. If we were to add heat to the saturated water, it would first boil away with no change in temperature (remember latent heat?) and then become superheated if still more heat were added to the vapor (steam) after it had all turned to a vapor.
Answer:
Adenine forms two hydrogen bonds with thymine;
guanine forms three hydrogen bonds with cytosine
Explanation:
There are three hydrogen bonds between guanine and cytosine. Between adenine and thymine, two hydrogen bonds form. Complementary pairs always include one base of purine and one base of pyrimidine.
Answer:
C3H6O3
Explanation:
To find the emperical of the compound,you divide the percentage composition of each element by it's molar mass(C=12, H=1, O=16).
For C,40/12=3.33. For H,6.71/1=6.71
For O,53.19/16=3.33.
Then divide everything by the smallest value which is 3.33
For C,3.33/3.33=1. For H,6.71/3.33=~2.
For O,3.33/3.33=1.
Emperical formula=CH2O
Molecular formula=(CH2O)n=90
(12+2*1+16)n=90
30n=90, n=3
molecular formula=(CH2O)3
molecular formula of lactic acid=C3H6O3.
The genus is a lower classification level that lies below family and above species . Species is the fundamental category of closely related organisms that lies below the genus .
Answer:
0.015 moles
Explanation:
- One mole of a compound contains molecules equivalent to the Avogadro's constant, 6.022 × 10^23.
- That is, 1 mole of a compound will have 6.022 × 10^23 molecules.
In our case, We are given 8.96 x 10^21 molecules of KBr
We need to find the number of moles in 8.96 x 10^21 molecules
1 mole of KBr = 6.022 × 10^23 molecules.
8.96 x 10^21 molecules = ?
Therefore;
(1 × 8.96 x 10^21 molecules ) ÷ 6.022 × 10^23 molecules.
= 1.488 × 10^-2 moles
= 0.01488 moles
= 0.015 moles
