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3 years ago

14

Determine the length of the object shown 1.2 cm 1.3 cm 1.25 cm 1.250 cm

2 answers:

stiks02 [169]3 years ago

6 0

The correct answer is 1.25 because it is 1/2 of 1 1/2 and that is 1.25.

bogdanovich [222]3 years ago

5 0

The correct answer is C. 1.25 cm.

If you can see, the head of the nail stops right in the middle of the 2nd and 3rd lines after 1. This means it is 1 and .2+ .05 or 1.25.

Hope this helps!

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If you have a pci express version 2 video card, how many pins will the power connector have if the card requires extra power?

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4 years ago

True or false? Atmospheric pressure increases with height

VLD [36.1K]

Answer:

True

Explanation:

5 0

4 years ago

Read 2 more answers

A liquid with a density of 900kg/m 3 is stored in a pressurized, closed storage tank. The tank is cylindrical with a 10m diamete

Orlov [11]

Answer:

18.62 m/s

Explanation:

Given that:

A liquid with a density of 900 kg/m 3 is stored in a pressurized, closed storage tank.

Diameter of the tank = 10 m

The absolute pressure in the tank above the liquid is 200 kPa = 200, 000 Pa

At pressure of 200 kPa ; the final velocity = 0

Atmospheric pressure at 5cm = 101325 Pa

We are to calculate the initial velocity of a fluid jet when a 5cm diameter orifice is opened at point A?

By using Bernoulli's theorem between the shaded portion in the diagram;

we have:

$Pa \ + \ \frac{1}{2} \ \delta \ v^2_1 \ + \ \delta gy_1 = P + \delta gy_2$

$\frac{1}{2} \ \delta \ v^2_1 \ = P + \delta gy_2 - \ \delta gy_1 - Pa$

$\frac{1}{2} \ \delta \ v^2_1 \ = \delta g(y_2 -y_1 )+ ( P - Pa )$

$v_1 \ = \sqrt{ \frac {2 \ \delta g(y_2 -y_1 )+ 2 ( P - Pa )}{\delta}}$

where;

Pa = atmospheric pressure = 101325 Pa

$\delta$ = density of liquid = 900 kg/m³

$v_1$ = initial velocity = ???

g = 9.8 m/s²

$y_1$ = height of the hole from the buttom

$y_2$ = height of the liquid surface from the button

$v_1 \ = \sqrt{ \frac {2*900*9.8(7 - 0.5 )+ 2 ( 200,000 - 101325 )}{900}}$

$v_1 = 18.62 \ m/s$

Thus, the initial velocity of the fluid jet = 18.62 m/s

3 0

3 years ago

Suppose that a car traveling to the west (the - x direction) begins to slow down as it approaches a traffic light. Which stateme

Amanda [17]

Answer:

(A) it's acceleration is negative but but it's velocity is positive

Explanation:

In the question it is given that begins to slow down so its speed is decreasing it is does not means that its speed is negative

For example let first the velocity of the car is 30 m/sec and when its velocity decreases it becomes 20 m/sec in 5 sec

So it is not negative at all

Now the acceleration is the rate of change of velocity

$a=\frac{dv}{dt}$

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So acceleration is negative here

So option (a) will be the correct option

4 0

3 years ago