2H₂ + O₂ -> 2H₂O. In this equation, write the coefficient numbers<br><br><br> PLEASE HELP MEEE

What process takes place before an article is published in a scientific journal/

Goshia [24]

Before an article is published in a scientific journal or in any "peer-reviewed" journal the article is reviewed thoroughly by scholars from the journal as well as peers or scholars of the articles author from the same field. This process occurs to provide credibility to the ideas being published and so that readers and other scholars can rely on the validity of the material being published.

7 0

3 years ago

What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i

UNO [17]

Answer:

$Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)$

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

$Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-$

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

$Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)$

The net equation is then:

$Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)$

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

$Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-$

Actual cathode half-equation:

$Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)$

Actual net reaction:

$Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)$

6 0

3 years ago

What is the difference between alkali metals and halogens?

Airida [17]

<h3>→soft and reactive metals. </h3>

Explanation:

<h3>Alkali metals are soft and reactive metals. They react vigorously with water and become more reactive. And other hand halogens are reactive non metals. ... Halogens can be solid, liquid, gaseous at room temperature and the melting point increase when they get bigger.</h3>

<h2>#CAREYINGTOLEARN❤️</h2>

4 0

3 years ago

Read 2 more answers

Please, I need help with this problem.

alexgriva [62]

انا عندي عندي في البيت عندي شغل في

3 0

3 years ago

An organic synthesis to make the pain reliever acetaminophen is supposed to produce 280 kg of product but instead produces 70 kg

Irina-Kira [14]

Answer: 75%

Explanation:

The following information can be gotten from the question:

Waste = 70kg

Theoretical yield = 280kg

Therefore, the actual yield will be the difference between the theoretical yield and the waste which will be:

= 280kg - 70kg = 210kg

The percent yield will now be:

= Actual yield / Theoretical yield × 100

= 210/280 × 100

= 3/4 × 100

= 75%

4 0

3 years ago

2H₂ + O₂ -> 2H₂O. In this equation, write the coefficient numbers PLEASE HELP MEEE