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zimovet [89]
2 years ago
5

What is the answer to this?

Physics
2 answers:
jeka57 [31]2 years ago
7 0

Answer:

I think it is the forth one

Art [367]2 years ago
5 0

Answer:

the last one. "of the thumbprint searing her immutable brow"

Explanation:

I hope it help you : )

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I kinda don’t know how to solve this I need help.
NemiM [27]

Answer:

the answer is 11 N left

Explanation:

there is more force being applied in the direction left, so the ball will move left. to find the net force that the ball will move in that direction subtract the force being applied in the opposite direction. so, 16N-5N=11N. your answer in 11 N left.

7 0
3 years ago
Can someone help me?
Alex777 [14]

Answer:

P is pressure ,rho(slanted p) is density,g is the acceleration due to gravity, v is velocity and h is height

Explanation:

6 0
3 years ago
A cell phone company relies on which kind of waves in order to provide service for its customers?
Tanzania [10]
Radio waves are what cell phone company rely on
4 0
3 years ago
Read 2 more answers
ANSWER FOR BRAINLIEST PLS AND FAST
sleet_krkn [62]

Answer:

The xylem distributes water and dissolved minerals upward through the plant, from the roots to the leaves. The phloem carries food downward from the leaves to the roots. Xylem cells constitute the major part of a mature woody stem or root.

Explanation:

brainliest pls

8 0
2 years ago
Read 2 more answers
There are four charges, each with a magnitude of 2.06 µC. Two are positive and two are negative. The charges are fixed to the co
mars1129 [50]

Answer:

0.208 N

Explanation:

We are given that

q_1=q_2=2.06\mu C=2.06\times 10^{-6} C

q_3=q_4=-2.06\mu C=-2.06\times 10^{-6} C

Distance,d=0.41 m

The magnitude of the net electrostatic force experienced by any charge at point 4

Net force,F_{net}=\sqrt{F^2_1+F^2_3+2F_1F_3cos90^{\circ}}-F_2

F_1=F_3=F

F_{net}=\sqrt{F^2+F^2+0}-F_2

F_{net}=\sqrt 2F-F_2

F=\frac{kq^2}{d^2}

F_2=\frac{Kq^2}{2d^2}

F_{net}=\frac{\sqrt 2kq^2}{d^2}-\frac{kq^2}{2d^2}=\frac{kq^2}{d^2}(\sqrt 2-\frac{1}{2})

Where k=9\times 10^9

F_{net}=\frac{9\times 10^9\times (2.06\times 10^{-6})^2}{(0.41)^2}(\sqrt 2-\frac{1}{2})

F_{net}=0.208 N

3 0
3 years ago
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