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netineya [11]
3 years ago
11

Mass is sometimes described as the difficulty of acceleration of an object. How does Newton's second law agree with this descrip

tion?
Physics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.

If the mass increases, it's harder to accelerate

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Savanna regions developed during the Triassic period.
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A student walks 24 m from her math class and then turns 90° and walks 10 m to her locker, which is directly north of her class.
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Add 24 + 10 = 34


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~Aceofdiamonds14
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A polarized Light of intensity I0 is incident on an analyzer. What should the angle between the axis of polarization of the ligh
Svetradugi [14.3K]

Answer:

The the angle between the axis of polarization of the light and the transmission axis of the analyzer is 52⁰.

Explanation:

Given;

I₀  as incident light intensity

The intensity of a linearly polarized light passing through a polarizer is given by Malus' law:

I = I₀Cos²θ

where;

I is the intensity after passing through the analyzer

θ is the the angle between the axis of polarization of the light and the transmission axis of the analyzer.

If 38% of the total intensity is transmitted, then I = 38% of I₀ = 0.38I₀

0.38I₀ = I₀Cos²θ

0.38 = Cos²θ

Cosθ = √0.38

Cosθ = 0.6164

θ  = Cos⁻¹ (0.6164)

θ  = 51.95° = 52⁰

Therefore, the angle between the axis of polarization of the light and the transmission axis of the analyzer to allow 38% of the total intensity to be transmitted is 52⁰.

3 0
3 years ago
Objects with masses of 255 kg and a 555 kg are separated by 0.390 m.
eimsori [14]

Answer:

(a). The net gravitational force is 4.20\times10^{-6}\ N

(b). The position is at 0.232 m.

Explanation:

Given that,

Mass of one object M = 255 kg

Mass of another object M'= 555 kg

Separation = 0.390 m

(a). We need to calculate the net gravitational force

Using formula of force

F_{net}=\dfrac{GM'm}{r^2}-\dfrac{GMm}{r^2}

F_{net}=\dfrac{Gm(M'-M)}{r^2}

Put the value into the formula

F_{net}=\dfrac{6.67\times10^{-11}\times32.0(555-255)}{(0.390)^2}

F_{net}=4.20\times10^{-6}\ N

The net gravitational force is 4.20\times10^{-6}\ N

(b). We need to calculate the position

Force from 555 mass = Force from 255 mass

\dfrac{Gm\times555}{x^2}=\dfrac{Gm\times255}{(0.390-x)^2}

555(0.390-x)^2=255x^2

300x^2-0.78x+84.4155=0

x=0.232\ m

The position is at 0.232 m.

Hence, (a). The net gravitational force is 4.20\times10^{-6}\ N

(b). The position is at 0.232 m.

5 0
3 years ago
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