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bagirrra123 [75]
3 years ago
14

How do you sound waves transfer energy

Physics
2 answers:
Lady bird [3.3K]3 years ago
8 0

In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles.

MARK ME BRAINLIEST PLEASE!!!!

Mariulka [41]3 years ago
8 0

Answer:

Sound waves transfer energy by causing successive compressions and rarefactions in the particles of the medium without transporting the medium particles themselves.

Explanation:

Sound in solids can also manifest as transverse waves, causing crests and troughs in the propagation medium. Waves can be characterized by two basic parameters: amplitude and frequency. Focusing on a single point vibrating in a medium excited by a sound wave, amplitude is the maximum distance traveled by the vibrating point relative to its rest position. Taking a snapshot of a propagating sound wave at any instance shows consecutive compressions and rarefactions, regions in which the medium material is compressed together and spread widely apart, respectively. The distance between the centers of two successive compressions or rarefactions is the wavelength of the wave. The frequency is the inverse of the wavelength, so the larger the frequency, the smaller the wavelength. Having a higher frequency makes the wave have a larger number of more closely-grouped compressions and rarefactions as it propagates. As the amplitude and frequency of the wave increase, the energy transferred by the propagation of the wave also increases. Extremely short but low-amplitude ultrasonic waves can be used to heat polymer materials and weld them together.

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The average Intensity of the electromagnetic field due to sunlight at the surface of the earth is 1400 W/m^2. Calculate the maxi
Ann [662]

Answer:

1027 N/C

3.42 x 10⁻⁶ T

Explanation:

I = Intensity of electromagnetic field = 1400 W/m²

E₀ = Maximum value of electric field

Intensity of electromagnetic field is given as

I = (0.5) ε₀ E₀² c

1400 =  (0.5) (8.85 x 10⁻¹²) (3 x 10⁸) E₀²

E₀ = 1027 N/C

B₀ = maximum value of magnetic field

using the equation

E₀ = B₀ c

1027 = B₀ (3 x 10⁸)

B₀ = 3.42 x 10⁻⁶ T

4 0
3 years ago
When fertilized what will the ovary grow into on a flower
densk [106]
The fertilised ovule<span> goes on to form a seed, which contains a food store and an embryo that </span>will<span> later </span>grow into<span> a new plant</span>
7 0
4 years ago
Can someone help me please??<br> This question is confusing to me:(
puteri [66]
Its d. the water isn't moving the fish, and that's how they remain stationary. they don't have any currents pushing on them. if this is wrong, its c, which is practically the same thing. but its most likely d.
7 0
4 years ago
Suatu sistem gas berada didalam ruang yang fleksibel. Pada awalnya gas berada pada kondisi P1 = 1,5 × 10 pangkat 5 N/m2, T1 = 27
enot [183]

Answer:

16.00L

Explanation:

First you calculate the number of moles in the system:

PV=nRT\\\\n=\frac{PV}{RT}\\\\n=\frac{(1.5*10^5N/m^2)(12L)}{(0.082L.atm/mol.K)(300.15K)}=73134.16\ mol

To find the new volume of the system you use the following formula for an isobaric procedure:

T_2-T_1=\frac{P}{nR}(V_2-V_1)\\\\V_2=\frac{nR}{P}(T_2-T_1)+V_1\\\\V_2=\frac{(73134.16\ mol)(0.082L.atm/mol.K)}{1.5*10^5N/m^2}(400.15-300.15)K+12L\\\\V_2=16.00L

hence, the new volume is 16.00L

6 0
4 years ago
When radioactive tracers are used for medical scans, the tracers both decay in the body via radiation, as well as being excreted
irinina [24]

Answer:

Effective half-time of the tracer is 3.6 days

Explanation:

The formula for calculating the decay due to excretion for the first process is ;

\frac{dN_1}{dt } = - \lambda _e N_o

here ;

N_o = initial number of tracers

Then to the second process ; we have :

\frac{dN_2}{dt } = - \lambda _e N_o

The total decay is as a result of the overall process occurring ; we have :

\frac{dN_{total}}{dt } = \frac{dN_1}{dt} + \frac{dN_2}{dt}   ------ (1)

here ;

\frac{dN_{total}}{dt } = \lambda _{total} N_o

Putting the values in (1);we have :

- \lambda _{Total} N_o = - \lambda_e N_o + ( -\lambda r N_o})

\lambda _{Total} = \lambda_e + \lambda r

As we also know that:

\frac{1}{t_{1/2}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}

\frac{1}{t_{1/2}}_{effective}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}

\frac{1}{t_{1/2}}_{effective}} = \frac{9+6}{9*6}

\frac{1}{t_{1/2}_{effective}}}=\frac{15}{54}

t_{1/2}_{effective}} = \frac{54}{15}

= 3.6 days

5 0
4 years ago
Read 2 more answers
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