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MrMuchimi
3 years ago
15

A student walks 24 m from her math class and then turns 90° and walks 10 m to her locker, which is directly north of her class.

What is her total displacement?
Physics
2 answers:
givi [52]3 years ago
4 0
Add 24 + 10 = 34


Hope i Helped :)


~Aceofdiamonds14
Pachacha [2.7K]3 years ago
3 0
Hello!

Answer :
24+10 = 34
Good Lessons!
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In this example we see how thermal expansion can actually throw off the accuracy of a length-measuring device—namely, a tape mea
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The new length is 50.00885m

Explanation:

linear thermal expansion coefficient Fe 11.8e-6 /K

The new length can be determined using the following equation:

∆L/L = α∆T, where α is linear thermal expansion coefficient

∆L = Lα∆T = 50(11.8e-6)(35-20) = 0.00885 m

New length = ( 50.000 + 0.00885)m =

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What type of specialized training is necessary to learn the skills needed to work in this career field
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DONTKNOW NEED CAREER FILD FIRST TO ANWSER

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Conservation equations are powerful equations, because of how versatile and flexible they are to different physical situations.
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b) false

Explanation:

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A 15kg hoop with a radius of 3 m is rolling at on a level surface when it reaches a 25 degree incline. If it reaches a height of
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The initial velocity of the hoop is determined as 8.854 m/s.

<h3>Conservation of energy</h3>

The initial velocity of the hoop can be determined from the principle of conservation of energy.

Final potential energy = Initial kinetic energy

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

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8.854 m/s = v

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4 0
2 years ago
The 630-nm light from a helium-neon laser irradiates a grating. The light then falls on a screen where the first bright spot is
dimaraw [331]

Answer:

464.8 nm

Explanation:

The second wavelength of light can be calculated using the next equation:

\lambda = \frac{x*d}{L}        

<u>Where:</u>

<em>λ : is the wavelength of light</em>

<em>x: is the distance from the central maximum</em>

<em>d: is the distance between the spots                      </em>

<em>L: is the lenght from the screen to the bright spot</em>

For the first wavelength of light we have:

\lambda_{1} = \frac{x_{1}*d}{L}

630 \cdot 10^{-9} m = \frac{0.61 m*d}{L}

\frac{d}{L} = \frac{630 \cdot 10^{-9} m}{0.61 m} = 1.033 \cdot 10^{-6}  (1)    

For the second wavelength of light we have:

\lambda_{2} = \frac{x_{2}*d}{L}

\lambda_{2} = 0.45 m*\frac{d}{L}   (2)  

By entering equation (1) into equation (2) we have:

\lambda_{2} = 0.45 m* 1.033 \cdot 10^{-6} = 4.648 \cdot 10^{-7} m = 464.8 nm

Therefore, the second wavelength is 464.8 nm

I hope it helps you!          

3 0
3 years ago
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