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Papessa [141]
3 years ago
9

Find the current in the thin straight wire if the magnetic field strength is equal to 0.00005 T at distance 5 cm. ​

Physics
1 answer:
Elodia [21]3 years ago
3 0

Answer:

Answer

Correct option is

A

5×10

−6

tesla

I=5A

x=0.2m

Magnetic field at a distance 0.2 m away from the wire.

B=

2πx

μ

0

I

=

2π×0.2

4π×10

−7

×5

=10×5×10

−7

=5×10

−6

tesla

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Answer:

Isotope it will have a different number of neutrons than normal

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Standard Heat of Formation: The enthalpy change for the formation of 1 mol of a substance in its standard state from its constit
ArbitrLikvidat [17]

Answer:

True

Explanation:

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Determine the projection (magnitude and sign), or component, of vector v1 along the direction of vector v2. Your answer could be
professor190 [17]

Answer:

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Explanation:

V1 = (-5, 7, 2)

V2 = (3, 1, 2)

Projection of v1 along v2, we use the following formula

=\frac{\overrightarrow{V1}.\overrightarrow{V2}}{V2}

So, the dot product of V1 and V2 is = - 5 (3) + 7 (1) + 2 (2) = -15 + 7 + 4 = -4

The magnitude of vector V2 is given by

= \sqrt{3^{2}+1^{2}+2^{2}}=3.74

So, the projection of V1 along V2 = - 4 / 3.74 = - 1.07 ft

Thus, the projection of V1 along V2 is - 1.07 ft.

so we need to find the direction of v2

7 0
3 years ago
If eight water waves pass an ocean buoy each minute, and successive wave crests are 20 m apart, find the wave speed:____________
Llana [10]

Answer:

The wave speed is calculated below:

Explanation:

Given,

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Now,

wave speed = 20 m × \frac{8}{60} s^{-1}

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4 0
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