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kolezko [41]
3 years ago
7

What will be the gravitational force between two heavenly bodies if the masses of both are tripled keeping the distance between

them constant
​
Physics
2 answers:
Leona [35]3 years ago
8 0

If the mass of one of the objects is tripled, then the force of gravity between them is tripled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

Kruka [31]3 years ago
5 0

Answer:

If the mass of one of the objects is tripled, then the force of gravity between them is tripled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces

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If you push a book against a wall hard enough, it will not slide down even though gravity is pulling it. Use what you know about
Rashid [163]

The frictional force is too much compared to the gravitational force

Explanation:

This is because of the great amount of frictional force between the book and the wall.

Also, the force of gravity on the book is not high enough to cause motion of the book to slide downs.

Frictional force is a force that opposes motion.

  • For the book to slide down, it must overcome the force of friction acting on it opposite to the direction of gravity.
  • According to newton's first law 'a body will remain in its state of rest or uniform motion unless acted upon by an external force'.
  • Assuming the external force is gravitational force, clearly we see that the force is less than the frictional exerted on the book by pinning it to the wall.
  • This frictional force is a static friction that is on a body at rest, it must be overcome by a larger force before motion takes place.

           Fr  >  fg

Fr is the frictional force

fg is the gravitational force

learn more:

Newton laws brainly.com/question/11411375

#learnwithBrainly

3 0
4 years ago
Which law explains why your head would hurt if you bumped it against the door?
eimsori [14]
Newtons law of motion
3 0
3 years ago
Match the technology that uses radio waves to the field in which it is used.
gayaneshka [121]

Answer:

magnetic resonance imaging

7 0
3 years ago
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Stolb23 [73]

Answer:

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3 0
3 years ago
A mule is harnessed to a sled having a mass of 246 kg, including supplies. The mule must exert a force exceeding 1210 N at an an
zimovet [89]

(a) 1800 N

The equation of the forces along the vertical direction is:

F sin \theta + N - mg = 0

where

F sin \theta is the component of the applied force along the vertical direction

N is the normal force on the sled

mg is the weight of the sled

Substituting:

F = 1210 N

m = 246 kg

\theta = 30.3^{\circ}

We find N:

N=mg-F sin \theta = (246)(9.8)-(1210)(sin 30.3^{\circ})=1800 N

(b) 0.580

The equation of the forces along the horizontal direction is:

F cos \theta - \mu_s N = 0

where

F cos \theta is the horizontal component of the push applied by the mule

\mu_s N is the static frictional force

Substituting:

F = 1210 N

N = 1800 N

\theta = 30.3^{\circ}

We find \mu_s, the coefficient of static friction:

\mu_s = \frac{F cos \theta}{N}=\frac{(1210)(cos 30.3^{\circ})}{1800}=0.580

(c) 522 N

In this case, the force exerted by the mule is

F= 6.05 \cdot 10^2 N = 605 N

So now the equation of the forces along the horizontal direction can be written as

F cos \theta - F_f = 0

where

\theta=30.3^{\circ}

and F_f is the new frictional force, which is different from part (b) (because the value of the force of friction ranges from zero to the maximum value \mu N, depending on how much force is applied in the opposite direction)

Solving the equation,

F_f = F cos \theta = (605)(cos 30.3^{\circ})=522 N

6 0
3 years ago
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