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mr Goodwill [35]
2 years ago
12

A wave hits a wall as shown. As the wave interacts with a wall, which kind of wave interaction is shown? absorption diffraction

refraction reflection

Physics
2 answers:
dangina [55]2 years ago
8 0
The answer is reflection.

The drawing is simple but illustrates the concept beautifully.
lorasvet [3.4K]2 years ago
8 0

The correct answer to the question is reflection.

EXPLANATION:

Before coming into any conclusion, first we have to understand reflection.

Reflection is the type of phenomenon in which a wave is reflected back to the same medium when it  incidents on a obstacle. The obstacle may be any opaque body, mirror etc.

As per the diagram, the wave incidents obliquely on the wall.

After incident on the wall, the wave is reflected back to the same medium.Here, the wall acts as a obstacle. This property of wave is called as reflection.

Diffraction and reflection can not be the suitable answer for it . It is so because diffraction refers to the bending nature of light at the edge of an obstacle while refraction is the optical phenomenon in which the light ray will be bent towards or away from the normal at the interface of the refracting surface.

Hence, the correct answer to the question is reflection.

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What is the equivalent of 0° C in Kelvin?<br> Help will give brainiest
givi [52]

Answer:

273.15 dat is the answer im pretty sure

8 0
3 years ago
A car is travelling at a constant speed of 26.5 m/s. Its tires have a radius of 72 cm. If the car slows down at a constant rate
maksim [4K]

Answer:

Magnitude of angular acceleration = -3.95 rad/s²

Explanation:

Angular acceleration is the ratio of linear acceleration and radius.

That is

        \texttt{Angular acceleration}=\frac{\texttt{Linear acceleration}}{\texttt{Radius}}\\\\\alpha =\frac{a}{r}

Radius = 72 cm = 0.72 m

Linear acceleration is rate of change of velocity.

a=\frac{11.7-26.5}{5.2}=-2.85m/s^2

Angular acceleration

        \alpha =\frac{a}{r}=\frac{-2.85}{0.72}=-3.95rad/s^2

Angular acceleration = -3.95 rad/s²  

Magnitude =  3.95 rad/s²     

4 0
3 years ago
The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the drag force?
timurjin [86]

Answer: The drag force goes up by a factor of 4

Explanation:

The <u>Drag Force</u> equation is:

F_{D}=\frac{1}{2}C_{D}\rho A_{D}V^{2} (1)

Where:

F_{D} is the Drag Force

C_{D} is the Drag coefficient, which depends on the material

\rho is the density of the fluid where the bicycle is moving (<u>air in this case) </u>

A_{D} is the transversal area of the body or object

V the bicycle's velocity

Now, if we assume C_{D}, \rho and A_{D} do not change, we can rewrite (1) as:

F_{D}=C.V^{2} (2)

Where C groups all these coefficients.

So, if we have a new velocity V_{n} , which is the double of the former velocity:

V_{n}=2V (3)

Equation (2) is written as:

F_{D}=C.V_{n}^{2}=C.(2V)^{2}

F_{D}=4CV^{2} (4)

Comparing (2) and (4) we can conclude<u> the Drag force is four times greater when the speed is doubled.</u>

7 0
3 years ago
Increasing the amount of current that flows through a wire ______ the strength of an electromagnet
Anestetic [448]

Electromagnet is in form of solenoid

and the magnetic field due to solenoid is given as

B = \mu_0 n i

here

i = current in the loop

so when we increase the current in electromagnet the magnetic field of the solenoid will increase

this will increase the strength of the electromagnet

so the answer would be

<em>INCREASE</em>

7 0
3 years ago
Read 2 more answers
A car mass of 1.2 x 10 kilograms starts from rest and attains a speed of 20 meters/seconds in 5 seconds. What net force acted on
lorasvet [3.4K]

Net force on the car=F=4.8 x 10³ N

Explanation:

mass of car= 1.2 x 10³ Kg

initial velocity= Vi=0

Final velocity= Vf= 20 m/s

time = t= 5 s

Using kinematic equation,

Vf= Vi + at

20= 0 + a (5)

5 a=20

a= 20/5

a= 4 m/s²

Now force is given by F = ma

F= 1.2 x 10³ (4)

F=4.8 x 10³ N

7 0
2 years ago
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