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mr Goodwill [35]
3 years ago
12

A wave hits a wall as shown. As the wave interacts with a wall, which kind of wave interaction is shown? absorption diffraction

refraction reflection

Physics
2 answers:
dangina [55]3 years ago
8 0
The answer is reflection.

The drawing is simple but illustrates the concept beautifully.
lorasvet [3.4K]3 years ago
8 0

The correct answer to the question is reflection.

EXPLANATION:

Before coming into any conclusion, first we have to understand reflection.

Reflection is the type of phenomenon in which a wave is reflected back to the same medium when it  incidents on a obstacle. The obstacle may be any opaque body, mirror etc.

As per the diagram, the wave incidents obliquely on the wall.

After incident on the wall, the wave is reflected back to the same medium.Here, the wall acts as a obstacle. This property of wave is called as reflection.

Diffraction and reflection can not be the suitable answer for it . It is so because diffraction refers to the bending nature of light at the edge of an obstacle while refraction is the optical phenomenon in which the light ray will be bent towards or away from the normal at the interface of the refracting surface.

Hence, the correct answer to the question is reflection.

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Each of the rods depicted below were machined from same stock metal. They were originally machined to be the same length, but th
Shkiper50 [21]

The force required to extend a rod increases as the cross sectional area

increases.

The rod that experiences the largest force is <u>rod B</u>

Reason:

The elongation of a rod by the application of a force is given by the

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\Delta L = \dfrac{F \cdot L}{A \cdot E}

From the above equation, we have that the elongation is inversely

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Therefore, the force required to extend the length of a rod by a specific

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The rod that experiences the largest force is the rod with the largest cross

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Learn more here:

brainly.com/question/12937199

4 0
2 years ago
Ejection of Electrons from Hydrogen by Incident Photons Light of wavelength 80 nm is incident on a sample of hydrogen gas, resul
timofeeve [1]

Answer:

a)   K_{max} = 1.9 eV = 3.04 10⁻¹⁹ J,b ) This means that some electrons are at the first excited level of the hydrogen atom, which is highly likely as the temperature rises.

Explanation:

a) To calculate the maximum kinetic energy of the expelled electrons let's use the relationships of the photoelectric effect

      K_{max}= h f - Φ

Where K is the kinetic energy, h the Planck constant that is worth 6.63 10⁻³⁴ Js, f the frequency and Φ the work function

The speed of light is related to wavelength and frequency

     c = λ f

Let's analyze the work function, it is the energy needed to start an electron from a metal, in this case to start an electron from a hydrogen atom its fundamental energy is needed, so

     Φ= E₀ = 13.6 eV

let's replace and calculate the energy of the incident photon

     E = h c / λ

     E = 6.63 10⁻³⁴ 3 10⁸/80 10⁻⁹

     E = 2,486 10⁻¹⁸ J

Let's reduce to eV

     E = 2,486 10⁻¹⁸ (1 eV / 1.6 10⁻¹⁹)

     E = 15.5 eV

Now we can calculate the kinetic energy

     K_{max}= h c / f - fi

      K_{max} = 15.5 -13.6

     K_{max} = 1.9 eV

b)     Extra energy = 10.2 eV

The total kinetic energy of electrons is

       Total kinetic energy = 1.9 +10.2 = 12.1 eV

For the calculation we are assuming that all the electors are in the hydrogen base state, but for temperatures greater than 0K some electors may be in some excited state, so less energy is needed to tear them out of hydrogen atom.

Let's analyze this possibility

      ΔE = E photon - Total kinetic energy electron

      ΔE = 15.5 - 12.1

      ΔE = 3.4 eV

If we use the Bohr ratio for the hydrogen atom

     E_{n} = 13.606 / n2

     n = √ 13.606 / En

     n = √ (13606 / 3.4)

     n = 2

This means that some electrons are at the first excited level of the hydrogen atom, which is highly likely as the temperature rises.

8 0
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Answer:

it depends on temperature^^

Explanation:

hope this helped^^

8 0
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Answer:

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