(a) The tension the musician must stretch it is 147.82 N.
(b) The percent increase in tension is needed to increase the frequency is 26%.
<h3>Tension in the string</h3>
v = √T/μ
where;
- v is speed of the wave
- T is tension
- μ is mass per unit length = 0.0144 kg / 0.6 m = 0.024 kg/m
v = Fλ
in fundamental mode, v = F(2L)
v = 2FL
v = 2 x 65.4 x 0.6 = 78.48 m/s
v = √T/μ
v² = T/μ
T = μv²
T = 0.024 x (78.48)²
T = 147.82 N
<h3>When the frequency is 73.4 Hz;</h3>
v = 2FL = 2 x 73.4 x 0.6 = 88.08 m/s
T = μv²
T = (0.02)(88.08)²
T = 186.19 N
<h3>Increase in the tension</h3>
= (186.19 - 147.82)/(147.82)
= 0.26
= 0.26 x 100%
= 26 %
Thus, the tension the musician must stretch it is 147.82 N.
The percent increase in tension is needed to increase the frequency is 26%.
Learn more about tension here: brainly.com/question/24994188
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1 Kg = 1,000g
Therefore 1.33 × 10^-7 g = 1.33 × 10^-10 kg
1m³ = 1,000,000cm³
Therefore 1 cm³ = 1 × 10^-6 m³
Dividing the mass per unit volume you get:
(1.33 × 10^-10 kg) ÷ (1 × 10^-6 m³)
= 1.33 × 10^(-10--6) = 1.33 × 10^(-10 + 6) = 1.33 × 10^-4 kg/m³
Density = 1.33 × 10^-4 kg/m³
Answer:
For small angles (✓ < 30 degrees), the period of a simple pendulum4can be approximated by: 3A radian is an angle measure based upon the circumference of a circle C =2⇡r where r is the radius of the circle. A complete circle (360 ) is said to have 2⇡ radians. Therefore, a 1/4 circle (90 )is⇡/2 radians.
Explanation:
-- From January 15 to February 6 is a period of 22 days.
-- The period of the full cycle of moon phases is 29.53 days.
-- So those dates represent (22/29.53) = 74.5% of a full cycle of phases.
-- That's almost exactly 3/4 of a full cycle, so on February 6, the moon would be almost exactly at <em>Third Quarter</em>. That's the <em>left half of a disk </em>(viewed from the northern hemisphere).