1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sladkih [1.3K]
2 years ago
11

would you like to explore outer space? Why or why not? If you could travel to any part of the galaxy at lightning speed would li

ke to see what is truly out in the universe would you do it? Why or why not?
Chemistry
1 answer:
morpeh [17]2 years ago
4 0

Answer:

Yes!

Explanation:

I think It would be fun!, Going thought space going from planet to planet. once i get back to earth i can make a document about my time in space.

You might be interested in
Energy transfer by convection is usually restricted to what type of substance? A. Solids only
Lunna [17]

My thought would be B) gases.

I could be wrong but that's what i'd say


4 0
3 years ago
If an atom has six electrons how many protons does it have
Sergio039 [100]
6 protons it have to be neutral 
7 0
3 years ago
Draw the lewis structure for bef2 in the box at the right, including lone pairs.
Kamila [148]

Answer :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and the unpaired electrons present in the molecule.

The given molecule is, BeF_2

Beryllium has '2' valence electrons and fluorine has '7' valence electrons. Beryllium is the central atom and fluorine is the terminal atom.

Total number valence electrons in BeF_2 = 2 + 2(7) = 16

According to the Lewis-dot structure, there are '4' number of bonding electrons and 12 number of non-bonding electrons (lone-pair).

The Lewis-dot structure is shown below.

3 0
2 years ago
What is the pH of 0.12M HNO3
Phoenix [80]

Answer:

pH= 0.92

Explanation:

HNO3-> H^+ +NO3^-

HNO3 is a strong acid, so it fully dissociates

[HNO3] = 0.12M    [H^+] = 0.12M  

pH= -log[H^+]

pH=-log[.12] = 0.92

pH = 0.92

4 0
3 years ago
If two gases A and B are at the same temperature and pressure, the ratio of their effusion rates is
Fed [463]

If the gases are at the same temperature and pressure, the ratio of their effusion rates is directly proportional to the ratio of the square roots of their molar masses:

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

Where

  • R₁ and R₂ are the rates of the two gas
  • M₁ and M₂ are the molar masses of the two gas

From the Graham's law equation, we can see that the ratio of the rates of effusion of the two gases is directly proportional to the square root of their molar masses

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

#SPJ1

3 0
2 years ago
Other questions:
  • How many grams of H2 are needed to react with 2.40 g of N2?
    9·1 answer
  • Which best explains why blood and the cytoplasm of cells are mainly composed of liquid water?
    6·2 answers
  • 1. Marisa determined the melting point of a substance to be 24.5C. Find the percent error of her measurement if the actual melti
    9·1 answer
  • Please help.This is due tomorrow.It's worth 2 grades.Please help.God bless u.Please and thankyou so much.
    8·1 answer
  • A balloon containing 0.10 moles of gas has a volume of 2.00 liters. If temperature and pressure remain constant, the new volume
    7·1 answer
  •  ¿Qué pasa con aquellas enfermedades para las cuales aún no hay vacunas?
    13·1 answer
  • The image below shows two nitrogen atoms. For these two atoms to form a stable molecule, N2, how many electrons would have to be
    8·1 answer
  • Which statement describes the role of consumers in an ecosystem?
    13·2 answers
  • Calculate the Volume of an object with dimensions measuring 22m x 15mm x 2.0mm
    15·1 answer
  • Difference between saturated unsaturted and supersaturatted
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!