Write the equation for changing atmospheric nitrogen and hydrogen to ammonia?

When Michelle's blood was testedthe chloride level was 0.45 g/dL. . What is this value in milliequivalents per liter? b. Accordi

ki77a [65]

Answer:

?what

Explanation:

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7 0

3 years ago

can a light object that was hit with a small force accelerate as rapidly as a heavier object hit with a big force? why or why no

Tcecarenko [31]

The acceleration is defined by force divided by the mass of the object. So, When the smaller object is hit by a small force, it can produce equal acceleration which is same as that of the bigger body hit with large force.

<h3><u>Explanation:</u></h3>

Force is defined as the product of the mass of the body its applied to and the acceleration of the body in the direction of the force. So acceleration is force divided by the mass of the body.

Let the mass of the smaller body be m and that of the larger body be M.

The smaller force applied on the smaller body be f and the larger force applied on the larger body be F.

So acceleration of the larger body = F/M.

Acceleration of the smaller body = f/m.

For the accelerations to be same,

F/M = f/m.

Or F/f = M/m.

So when the ratio of the force applied on two bodies is in ratio of their masses, the acceleration becomes equal.

3 0

3 years ago

Benzene is 92.3% carbon and 7.7% hydrogen. In anexperiment,

Marysya12 [62]

Answer:

The molecular formula of benzene = $C_{6}H_{6}$

Explanation:

$Moles =\frac {Given\ mass}{Molar\ mass}$

% of C = 92.3

Molar mass of C = 12.0107 g/mol

% moles of C = $\frac{92.3}{12.0107}$ = 7.6848

% of H = 7.7

Molar mass of H = 1.00784 g/mol

% moles of H = $\frac{7.7}{1.00784}$ = 7.6401

Taking the simplest ratio for C and H as:

7.6848 : 7.6401

= 1 : 1

The empirical formula is = $CH$

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12+ 1 = 13 g/mol

Molar mass = 78.0 g/mol

So,

Molecular mass = n × Empirical mass

78.0 = n × 13

⇒ n ≅ 6

<u>The molecular formula of benzene = $C_{6}H_{6}$ </u>

7 0

4 years ago

what is the empirical formula of vanadium 1 oxide given that 20.38 grams of vandium combines with oxygen to form 23.58 grams of

Alex

Answer:

The empirical formula is V₂O

Empirical formula of a compound is the formula that shows the simplest whole number ratio of the atoms of elements in a given compound. Empirical formula is normally calculated when the mass of each element in a compound is known or the percentage composition by mass of each element in a compound is known.

Step by Step Explanation:

Step 1: Percentage composition of each element

Percentage composition=(mass of an element/ mass of the compound)100%

Mass of Vanadium = 20.38 g

Mass of the compound = 23.58 g

% composition of Vanadium = (20.38 g/23.58 g) 100%

= 86.43 %

Mass of Oxygen = 23.58 g -20.38 g

= 3.2 g

% composition of oxygen = (3.2/g/23.58 g) 100%

= 13.57%

Step 2: Find the number of atoms of each element in the compound

Number of atoms = percentage composition/ atomic mass

Atomic mass of Vanadium = 50.94 g/mol

Number of atoms of V = 86.43 /50.94

= 1.6967

Atomic mass of oxygen = 16 g/mol

Number of atoms of O = 13.57/16

= 0.8481

Step 3: Find the simplest ratio of atoms

Vanadium : Oxygen

1.6967 : 0.8481

= 1.6967/0.8481 : 0.8481/0.8481

= 2: 1

Whole number ratio = 2 : 1

Therefore; the empirical formula is V₂O

8 0

3 years ago

Read 2 more answers

Define an ion in chemistry

REY [17]

Ion is an atom or molecule with a net electric charge due to loss or gain of one or more electrons.

4 0

4 years ago