Answer: LOL. I think thats how-
Answer:
7.41 × 10⁻⁵
Explanation:
Let's consider the basic dissociation reaction of trimethylamine (CH₃)N).
(CH₃)N + H₂O = (CH₃)NH⁺ + OH⁻
According to Brönsted-Lowry, in this reaction (CH₃)N is a base and (CH₃)NH⁺ is its conjugate acid. The pKb for (CH₃)N is 9.87. We can calculate the pKa of (CH₃)NH⁺ using the following expression.
pKa + pKb = 14
pKa = 14 - pKb = 14 - 9.87 = 4.13
Then, we can calculate the acid dissociation constant for (CH₃)NH⁺ using the following expression.
pKa = -log Ka
Ka = antilog - pKa = antilog -4.13 = 7.41 × 10⁻⁵
Explanation:
Mass = Density × Volume
where volume = 500ml and....
Density = 0.9901 g/ml
Mass = 0.9901 × 500
Mass = 495.05 g
Answer:
0.9875 mole O₂
Explanation:
Rxn => H₂ + ¹/₂O₂ => H₂O
from above reaction, 1 mol H₂ requires ¹/₂ mol O₂ then 1.975 mol H₂ requires ¹/₂(1.975 mol)O₂ or 0.9875 mol O₂.
Answer:I believe its A. There noble gasses so there happy with there electron count!
Explanation:
