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Savatey [412]
3 years ago
6

If a jet travels 350 m/s, how far will it travel each second?

Physics
2 answers:
77julia77 [94]3 years ago
6 0

Answer:

It will travel 350 meters each second.

Explanation:

The unit rate, 350 m/s, tells us that the jet will travel 350 meters per every second elapsed.

yaroslaw [1]3 years ago
3 0

Answer:

5.83 seconds

Explanation:

60 seconds in 1 minute

350 meters per second

350/60

=5.83

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Use the diagram to explain how convection occurs inside the earth. What could convection cause to occur on earths surface
liubo4ka [24]

Answer:

mantle convection is the very slow creeping motion of earths solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface.

3 0
2 years ago
Energy is conventionally measured in Calories as well as in joules. One Calorie in nutrition is one kilocalorie, defined as 1 kc
Sergeeva-Olga [200]

Answer:

a) The student must run flight of stairs to lose 1.00 kg of fat 709.5 times.

b) Average power

P(w)= 1062.07 [w]

P(hp)=1.42 [hp]

c) This activity is highly unpractical, because the high amount of repetitions he has to due in order to lose, just 1 Kg of fat.

Explanation:

First, lets consider the required amount of work to move the mass of the student. (considering running stairs just as a vertical movement)

Work:

W= F*d= m*g*d

Where m is the mass of the student, g is gravity (9.8 m/s) and d is the total distance going up the stairs (0.15m *85steps= 12.75m )

W= F*d= m*g*d=85* 9.8*12.75=10620.75 [J]

Converting from Joules to Kcals:

\frac{10620.75}{4186} =2.537 Kcal

Now lets take into account the efficiency of the human body (20%)

2.537 ---> 20%

 x       ---> 100%

x=\frac{2.537*100}{20} =12.685

So the student is consuming 12.685 KCals each time he runs up the stairs.

Now,

1 g --> 9 Kcals

1000 g --> 9000KCals

Burning 1 g of fat, requieres 9 KCals, 1000g burns 9000KCals. So in order to burn a 1Kg of fat:

\frac{9000Kcals}{12.685Kcals} =709.5 times

He must run up the stairs 709.5 times, to burn 1 Kg of fat.

********************

For b) just converting units, taking into account the time lapse. (53103.75 is the 100% of the energy in joules, from converting 12.685Kcals to joules)

Power=\frac{Joules}{Seconds} =\frac{53103.75}{50} =1062.075 [W]\\

P(hp)=\frac{P(w)}{745.7} =\frac{1062.075}{745.7} =1.42[hp]

*****

4 0
3 years ago
When all else remains the same, what effect would decreasing the focal length have on a convex lens?
aniked [119]
<h3>Answer;</h3>

<u>It would make the lens stronger. </u>

<h3>Explanation;</h3>
  • The focal length is the distance between the optical center or the center of the lens to the focal point of a convex or concave lens.
  • The power of the convex lens is lens ability to undertake refraction or bend light. It is given as the reciprocal of focal length.
  • Power of the lens = 1/ f; therefore the smaller the focal length the higher the power and the larger the focal length the lower the power.
  • Thus; decreasing the focal length of a convex lens makes the lens stronger.

4 0
3 years ago
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D is the answer most true
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What is the force of friction acting on the crate? I am offering 30 points.
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I think the answer is C


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