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3 years ago

In ΔEFG, the measure of ∠G=90°, the measure of ∠E=77°, and GE = 2.6 feet. Find the length of FG to the nearest tenth of a foot.

Mathematics

2 answers:

BigorU [14]3 years ago

8 0

Answer:

11.3

Step-by-step explanation:

BigorU [14]3 years ago

4 0

Answer:

FG=11.6 feet

Step-by-step explanation:

cos 77 degrees=2.6/FG (because this is a right triangle)

.22495=2.6/FG

FG=11.558 feet

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dem82 [27]

Answer:

The expression that represents Capri’s age is a + 4.

The expression that represents Portia’s age is a – 5.

Step-by-step explanation:

The expression that represents Capri's age is a + 4.

The expression that represents Portia's age is a -5.

To write an equation for this scenario, Capri's age needs to be equal to Portia’s age

The equation used to represent this scenario is a + a + 5 + 2 - 4 = 38.

Solving this equation will give Aziza's age.

Aziza'a age = a

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Capri's age = 4 + a

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3 years ago

Utiliza la formula De la distancia para calcular la medida De Los segmentos M(2,2) yN(5,-1)MN

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Answer:

$\huge{ \boxed{ \sf{ \sqrt{18} \: units}}}$

Step-by-step explanation:

$\star{ \sf{ \:Sea \: M (2, 2) \: (x1, y 1) \: y \: N (5, -1) \: sea \: (x2, y2).}}$

$\star{ \sf{ \: Usando \: la \: fórmula \: de \: la \: distancia}} :$

$\boxed{ \sf{distancia = \: \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{distancia \: = \: \sqrt{ {(5 - 2)}^{2} + {( - 1 - 2)}^{2} } }}$

$\mapsto{ \sf{distancia = \sqrt{ {(3)}^{2} + {( - 3)}^{2} } }}$

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$\mapsto{ \sf{distancia = \sqrt{18} \: units}}$

$\sf{¡Espero \: haber \: ayudado!}$

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3 years ago

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Answer:

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3 years ago

Round 18.159 to the nearest tenth

Mandarinka [93]

Answer:

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2 years ago

Mrs. Braddock has a bag containing 6 lipsticks, 4 eye shadows, 6 eye liners, and 5 mascaras. She will randomly choose one item f

Slav-nsk [51]

Answer:

The probability that she will not pull lipstick is 71%.

Step-by-step explanation:

The probability of an event <em>E</em> is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable number of outcomes

N = total number of outcomes

The contents in Mrs. Braddock's bag are:

Number of lipsticks = n (L) = 6

Number of eye shadows = n (S) = 4

Number of eye liners = n (E) = 6

Number of mascaras = n (M) = 5

Total number of items in the bag = N = 21

Consider that the probability of an event occurring is P. Then the probability of the given event not taking place is known as the complement of that event.

Complement of the given event is, 1 – P.

Compute the probability of selecting a lipstick as follows:

$P(L)=\frac{n(L)}{N}\\\\=\frac{6}{21}\\\\=\frac{2}{7}$

Compute the probability of not selecting a lipstick as follows:

$P(L^{c})=1-P(L)$

$=1-\frac{2}{7}\\\\=\frac{7-2}{7}\\\\=\frac{5}{7}$

Convert this probability into percentage as follows:

$\frac{5}{7}\times 100 = 71.4286\approx 71\%$

Thus, the probability that she will not pull lipstick is 71%.

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3 years ago

In ΔEFG, the measure of ∠G=90°, the measure of ∠E=77°, and GE = 2.6 feet. Find the length of FG to the nearest tenth of a foot.​

In ΔEFG, the measure of ∠G=90°, the measure of ∠E=77°, and GE = 2.6 feet. Find the length of FG to the nearest tenth of a foot.