Answer:
N = 148.10N
Explanation:
GIVEN
Weight =125 N
force = 35
angle =42°
since there is no vertical acceleration 
from
free body diagram
According to the following formula, the answer is 2,300 g or 2.3 kg:
Volume (m)/Mass (m) Equals Density (p) (V)
Here, the density is 1.15 g/mL, allowing the formula described above to result in a mass of 2.00 L:
p=m/V
1.15 g/mL is equal to x g/2.00 L or x g/2,000 mL.
2,000 mL of x g = 1.15 g of g/mL
2.3 kg or 2,300 g for x g.
<h3>How many grams of glucose are in a 1000ml bag of glucose 5?</h3>
Its active ingredient is glucose. This medication includes 50 g of glucose per 1000 ml (equivalent to 55 g glucose monohydrate). 50 mg of glucose is present in 1 ml (equivalent to 55 mg glucose monohydrate). A transparent, nearly colourless solution of glucose in water is what is used in glucose intravenous infusion (BP) at 5% weight-to-volume.
Patients who are dehydrated or who have low blood sugar levels get glucose intravenously. Other medications may be diluted with glucose intravenous infusion before being injected into the body. Other diseases and disorders not covered above may also be treated with it.
learn more about glucose intravenous infusion refer
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Answer:
compared to the incident angle, the refracted angle is 45.56⁰
Explanation:
From Snell's law;
n₁sin(I) = n₂sin(r)
Where;
n₁ is the refractive index of light in medium 1 = 1.2
n₂ is the refractive index of light in medium 2 = 1.4
I is the incident angle
r is the refractive angle
I = 56.439⁰
Applying snell's law
Therefore, compared to the incident angle, the refracted angle is 45.56⁰
3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:
(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v
where v is the velocity of the combined players. Solve for v :
450 kg•m/s - 320 kg•m/s = (155 kg) v
v = (130 kg•m/s) / (155 kg)
v ≈ 0.84 m/s
4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that
(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v
where v is the new velocity of the 4-kg ball. Solve for v :
30.6 kg•m/s - 5.2 kg•m/s = 9 kg•m/s + (4 kg) v
v = (16.4 kg•m/s) / (4 kg)
v = 4.1 m/s
Tensile strength is the amount of tension a material can hold, at least I hope that’s what it is.
