Answer:
SnF2
Explanation:
you divide by the smallest number which is 3.37
Answer :]
A.)Calculate the mass of ammonium sulfate that would be obtained by reacting with ammonia acid.
<em>Correct me if i'm wrong :]</em>
1.D 2.A that is pretty hard
Answer:
Chloroform= limiting reactant
0.209mol of CCl4 is formed
And 32.186g of CCl4 is formed
Explanation:
The equation of reaction
CHCl3 + Cl2= CCl4 + HCl
From the equation 1 mol of
CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4
From the question
25g of CHCl3 really with Cl2
Molar mass of CHCl3= 119.5
Molar mass of Cl2 = 71
Hence moles of CHCl3= 25/119.5 = 0.209mol
Moles of Cl2 = 25/71 = 0.352mol
Hence CHCl3 is the limiting reactant
Since 1 mole of CHCl3 gave 1mol of CCl4
It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4
Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g
Answer:
1,816 L
Explanation:
Molar concentration or molarity is a way to express the concentration of a chemical in terms of moles of substances per liter of solution.
To obtain the liters of this solution you must convert moles/L to g/L with formula weight (FW), thus:
0,1107 mol of KCl / L × (74,6 g / mol) = 8,258 g of KCl / L.
It means that in one liter you have 8,258 g of KCl. Thus, 15,00 g of KCl are contained in:
15,00 g × (1 L / 8,258 g) = 1,816 L
I hope it helps!
