Answer:
11.3 g.
Explanation:
Hello there!
In this case, since the combustion of butane is:
Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:
Therefore, the resulting mass of water is:
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Trick question: you just stated everything in the beakers.
Answer:
0.60 moles of Na₂SO₄
Explanation:
Molarity is an unit of concentration defined as the ratio between moles of solute and liters of solution.
A solution of Na₂SO₄ 0.40M contains 0.40 moles of solute (Na₂SO₄) per liter of solution.
As you have 1.5L of solution, moles of Na₂SO₄:
1.5L × (0.40mol / L) = <em>0.60 moles of Na₂SO₄</em>
Ranking of the atom from highest to lowest is as follows:
Highest
Arrow = from outer edge to center
2nd Highest
Arrow = second closest ring to the outer edge to center
3rd Highest
Arrow = middle circle to center
Lowest
Arrow = outer edge to middle circle
<span>2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
</span>
2 moles C6H6 -------------------- 6 moles H2O
8.73 moles C6H6 --------------- ( moles H2O)
( moles H2O) = 8.73 x 6 / 2
( moles H2O) = 52.38 / 2
= 26.19 moles of H2O
Molar mass H2O = 18.00 g/mol
1 mole -------------- 18.00 g
26.19 moles ----- ( mass of H2O)
mass of H2O = 26. 19 x 18.00 => 471.42 g of water
hope this helps!
