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Marta_Voda [28]
3 years ago
14

How many liters of 0.1107 M KCI contain 15.00 g of KCI (FW 74.6 g/mol)? O0.02227 L O 0.5502 L 01661 L O 1.816 L 18.16 L

Chemistry
1 answer:
Greeley [361]3 years ago
3 0

Answer:

1,816 L

Explanation:

Molar concentration or molarity is a way to express the concentration of a chemical in terms of moles of substances per liter of solution.

To obtain the liters of this solution you must convert moles/L to g/L with formula weight (FW), thus:

0,1107 mol of KCl / L × (74,6 g / mol) = 8,258 g of KCl / L.

It means that in one liter you have 8,258 g of KCl. Thus, 15,00 g of KCl are contained in:

15,00 g × (1 L / 8,258 g) = 1,816 L

I hope it helps!

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\boxed{\text{25. 20 L; 26. 49 K}}

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\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}

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\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}

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T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}

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